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3 years ago

0.35714285714 as a fraction?

Mathematics

1 answer:

Blababa [14]3 years ago

4 0

As a fraction it is 357/1000.
Simplify that it is 7/20

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At midnight, the temperatures is -4 degrees Celsius. At noon, the temperature is 20 degrees Celsius. By how many more degrees Ce

8_murik_8 [283]

24 degrees celcius
-4 + 4 = 0
0 + 20 = 20
20 + 4 = 24 degrees celcius

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2 years ago

Pleasee help me i will give you 40 points. in the boxes it says amount of money or amount of houses.

Montano1993 [528]

Answer: type it in quizlet

Step-by-step explanation:

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3 years ago

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a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.

ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: $\mathbf{Length = a -5}$ and $\mathbf{Width = a^2 + 5a + 25}$

The area is given as:

$\mathbf{Area = a^3 - 125}$

Express 125 as 5^3

$\mathbf{Area = a^3 - 5^3}$

Apply difference of cubes

$\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}$

$\mathbf{Area = (a - 5)(a^2 + 5a + 25)}$

The area of a rectangle is:

$\mathbf{Area = Length \times Width}$

So, by comparison:

$\mathbf{Length = a -5}$

$\mathbf{Width = a^2 + 5a + 25}$

Read more about areas at:

brainly.com/question/3518080

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2 years ago

If a = pi +3j - 7k, b = pi - pj +4k and the angle between a and is acute then the possible values for p are given by

PIT_PIT [208]

Answer:

The family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

Step-by-step explanation:

By Linear Algebra, we can calculate the angle by definition of dot product:

$\cos \theta = \frac{\vec a\,\bullet\,\vec b}{\|\vec a\|\cdot \|\vec b\|}$ (1)

Where:

$\theta$ - Angle between vectors, in sexagesimal degrees.

$\|\vec a\|, \|\vec b \|$ - Norms of vectors $\vec {a}$ and $\vec{b}$

If $\theta$ is acute, then the cosine function is bounded between 0 a 1 and if we know that $\vec {a} = (p, 3, -7)$ and $\vec {b} = (p, -p, 4)$ , then the possible values for $p$ are:

Minimum ( $\cos \theta = 0$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} > 0$

Maximum ( $\cos \theta = 1$ )

$\frac{p^{2}-3\cdot p -28}{\sqrt{p^{2}+58}\cdot \sqrt{2\cdot p^{2}+16}} < 1$

With the help of a graphing tool we get the family of possible values for $p$ are:

$(-\infty, -4) \,\cup \,(7, +\infty)$

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2 years ago

State whether the value for the unknown makes inequalities <br><br> 74/e < 12

Nezavi [6.7K]

Answer:

Yes

Step-by-step explanation:

74/e < 12

Since e is in the denominator, e can not be 0.

If e > 0,

74/e < 12

74 < 12e

e > 74/12

e < 37/6

If e < 0,

(When you multiply by e, which is a negative value, inequality reverses)

74 > 12e

e < 74/12

e < 37/6

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2 years ago

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