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Please help Person with the right answer I will mark Brainlyist

e-lub [12.9K]

Answer:

The equation in the standard form is

$y+2x=5$

Step-by-step explanation:

Given the points

(6, -7)

(4, -3)

Finding the slope between (6, -7) and (4, -3)

$\left(x_1,\:y_1\right)=\left(6,\:-7\right),\:\left(x_2,\:y_2\right)=\left(4,\:-3\right)$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{-3-\left(-7\right)}{4-6}$

$m=-2$

As the point-slope form is defined as

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -2 and the point (6, -7)

$y-y_1=m\left(x-x_1\right)$

$y-\left(-7\right)=-2\left(x-6\right)$

Writing the equation in the standard form form

As we know that the equation in the standard form is

$Ax+By=C$

where x and y are variables and A, B and C are constants

converting the equation in standard form

$y-\left(-7\right)=-2\left(x-6\right)$

$y+7=-2\left(x-6\right)$

subtract 7 from both sides

$y+7-7=-2\left(x-6\right)-7$

$y=-2x+5$

$y+2x=5$

Therefore, the equation in the standard form is

$y+2x=5$

7 0

3 years ago

What degree of rotation is represented on this matrix

Korvikt [17]

Answer:

Option B is correct

the degree of rotation is, $-90^{\circ}$

Step-by-step explanation:

A rotation matrix is a matrix that is used to perform a rotation in Euclidean space.

To find the degree of rotation using a standard rotation matrix i.e,

$R = \begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$

Given the matrix: $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

Now, equate the given matrix with standard matrix we have;

$\begin{bmatrix}\cos \theta & -\sin \theta \\ \sin \theta & \cos \theta \end{bmatrix}$ = $\begin{bmatrix}0 & 1 \\ -1 & 0\end{bmatrix}$

On comparing we get;

$\cos \theta = 0$ and $-\sin \theta =1$

As,we know:

$\cos \theta = \cos(-\theta)$

$\sin(-\theta) = -\sin \theta$

$\cos \theta = \cos(90^{\circ}) = \cos( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

and

$\sin \theta =- \sin (90^{\circ}) = \sin ( -90^{\circ})$

we get;

$\theta = -90^{\circ}$

Therefore, the degree of rotation is, $-90^{\circ}$

7 0

3 years ago

8=-10+m {-4/5} {-80} {18} {-2}

Alex787 [66]

Answer:

The answer is C.

Step-by-step explanation:

In order to find the value of m, you have to eliminate -10 on the right side by adding 10 to both sides :

8 = -10 + m

8 + 10 = -10 + m + 10

18 = m

m = 18

5 0

3 years ago

Read 2 more answers

A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5

Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: $\frac{X-\mu}{\sigma}$

Therefore

$\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}$

$\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}$

$-1.5\leq z\leq 2.5$

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

$P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270$

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0

3 years ago

Please answer this question correctly

Alex Ar [27]

Answer: it is 6

Step-by-step explanation: because they are the same length.

5 0

2 years ago