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3 years ago

HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

5 0

Setup is
y = k/x
8 = k/3
k = 24

Now use 6 for y
6 = 24/x
x = 24/6 = 4 or A

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On a school trip, 4 adults are required to supervise a

lara31 [8.8K]

Answer:

5 adults

Step-by-step explanation:

So 4 adults are taken for 32 children. We can use 32 divided by 4 to see how many children it takes to assign an adult. the answer to this would be 8. if 8 more children are added ( which would make 32+8 which is 40) than another adult would be needed.

8 0

3 years ago

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Convert 46,500 scientific notation

Shkiper50 [21]

46500....ok...pay attention....put a decimal behind the first number 4.6500 ....now start counting all the numbers to the right of the decimal...there are 4 numbers.....so ur answer is 4.65 x 10^4

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4 years ago

PLEASE PLEASE PLEASE HELP

Musya8 [376]

Answer:

The weight of large box = 13.75 kilograms

the weight of small box = 6.5 kilograms

Step-by-step explanation:

Given:

delivery of 2 large boxes and 3 small boxes has a total weight of 47 kilograms

delivery of 6 large boxes and 5 small boxes has a total weight of 115 kilograms.

Let x be the weight of large box

and y be the weight of small box

Make equation from the given information

2(weight of large box) + 3(weight of small box) = 47

2x + 3y = 47 -----------> equation 1

Do the same and make one more equation

6x + 5y = 115-----------> equation 2

Now we solve both equation using elimination method

Multiply the first equation by 3

6x + 9y = 141

6x + 5y = 115 (subtract both equations)

----------------------------------------------------

4y = 26

divide both sides by 4

So y= 6.5

Now plug in 6.5 for y and find out x

2x+3y = 47

2x + 3(6.5) = 47

2x + 19.5 = 47 (subtract 19.5 on both sides)

2x = 27.5

divide both sides by 2

x = 13.75

The weight of large box = 13.75 kilograms

the weight of small box = 6.5 kilograms

3 0

4 years ago

A fulcrum moving a resistance of 200 g has a distance to the fulcrum of 20 cm, the effort mass of 50 g has a distance to the ful

S_A_V [24]

Answer:

The ideal mechanical advantage (IMA) is $4$ .

Step-by-step explanation:

The ideal mechanical advantage is the ratio of length of longer lever $L_e$ to that of shorter lever $L_r$

IMA $\frac{L_e}{L_r}$

Please refer to the image attached.

We could see that the the resistance load moves $10\ cm$ cm towards the fulcrum so the distance of resistance load from fulcrum $= (20-10) =10\ cm$

Now the as the effort force moves $40\ cm$ towards the fulcrum overall distance from the fulcrum to the effort force (load) $=(80-40)=40\ cm$

Plugging the values of the distances in IMA formula we can have.

IMA $=\frac{(80-40)}{(20-10)} =\frac{40}{10} =4$ .

So the IMA of the fulcrum (simple machine) $= 4$

3 0

4 years ago

Write the equation of the line that<br> Passes through (-9,4) and 10,-2)

adell [148]

Answer: The first thing we need to do is find the slope--the rise over run. We can find it by using the formula:

(y2 - y1) / (x2 - x1), that is we subtract the x an y values of our two points and then divide:

(-4 - -10) / (9 - 9)

(-4 + 10) / (9 - 9)

6 / 0

We cannot divide by 0. Our slope is essentially infinity, or a straight line up and down. This means we take a look at the x-coordinate: 9. This means our equation is:

x = 9

because no matter what we use for y, x will always stay at 9

Step-by-step explanation:

also you pfp is cute as hell girl!

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3 years ago

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