Answer:
Your teacher is right, there is not enough info
Step-by-step explanation:
<h3>Question 1</h3>
We can see that RS is divided by half
The PQ is not indicated as perpendicular to RS or RQ is not indicates same as QS
So P is not on the perpendicular bisector of RS
<h3>Question 2</h3>
We can see that PD⊥DE and PF⊥FE
There is no indication that PD = PF or ∠DEP ≅ FEP
So PE is not the angle bisector of ∠DEF
Heya user
we have
7x - 6y and x + y
according to the question
( 7x - 6y ) + ( x + y )
→ 7x - 6 y +x + y
→ 8x - 5y
Hope This helps you
Answer:
28%
Step-by-step explanation:
I did it and it was right
Find their gradients using the change in y coords divided by the change in x coords. once you have the gradients (or slopes), multiply them by eachother - if the product is (-1) then theyre perpdendicular, if not, they are either parallel or intersect at a point
Answer:
D
Step-by-step explanation
I'd say it's PQR and TSR cause they match up in terms of the order of vertexes, and then you've got the angles of P and T that are in the middle of PR and TR, which are equal, and the sides PQ and TS. The angles are in between the sides.