Which is heavier 9 5/8 or 9 3/4 pounds

Marlene rides her bicycle to her friend jon's house and returns home by the same route. marlene rides her bike at constant spee

riadik2000 [5.3K]

To solve the problem:

<span>Let f = distance one way distance on level ground</span>

<span>
Let h = distance rode on the hill</span>

<span>
Write a time equation; where Time = distance/speed:</span>

<span>

level time + uphill time + downhill time + level time = 1hr</span>

<span>

Multiply equation by 18 to get rid of the denominators</span>

2f + 3h + h + 2f = 18

4f + 4h = 18

Simplify by dividing this by 4

<span>f + h = 4.5 miles is took her to get to Jon’s house.</span>

6 0

3 years ago

Solve for x in the function

Zinaida [17]

Answer:

4

Step-by-step explanation:

<h3>2^3= 2x2x2= 8 + 4 =12</h3><h3 /><h3>but it is 16 not 12 so 16 - 12 =4 so that should be ur awnser.</h3><h3 /><h3 /><h3 /><h3>In return can u answer the question that i just asked on my account</h3>

3 0

3 years ago

What is (40x33)+(4)x4??<br> Good luck

MrRa [10]

Answer:

1336

PLZ let me know if im wrong!!!

5 0

3 years ago

Find the area of a circle with radius = 12 yd. Use i æ3.14.

Anarel [89]

(A = π r²)

A = 144 π in^2

3 0

3 years ago

The weights of soy patties sold by a diner are normally distributed. A random sample of 25 patties yields a mean weight of 4.2 o

just olya [345]

Answer:

$t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2$

The degrees of freedom are given by:

$df =n-1=25-1=24$

And the p value would be given by:

$p_v = P(t_{24}>2) =0.0285$

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

Step-by-step explanation:

Data provided

$\bar X=4.2$ represent the sample mean for the weigths

$s=0.5$ represent the sample standard deviation

$n=25$ sample size

$\mu_o =4$ represent the value that we want to analyze

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We want to conduct a hypothesis in order to check if the true mean weigth is less than 4 or not, the system of hypothesis would be:

Null hypothesis: $\mu \leq 4$

Alternative hypothesis: $\mu > 4$

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing the info given we got:

$t=\frac{4.2-4}{\frac{0.5}{\sqrt{25}}}=2$

The degrees of freedom are given by:

$df =n-1=25-1=24$

And the p value would be given by:

$p_v = P(t_{24}>2) =0.0285$

And since the p value is lower than the significance level we have enough evidence to conclude that the true mean for this case is significantly hiher than 4. And the claim for this case is not appropiate

5 0

3 years ago