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antiseptic1488 [7]
3 years ago
6

Consider the following sets:

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
7 0

***********************m = 2 ****************************

bagirrra123 [75]3 years ago
4 0
U = {points on the coordinate plane}
A = {solutions to the equation y = 2x + 5}
B = {points on the line y = mx}

Value of the slope m so that  {2x + 5} ∩ {mx} =Ф
This means that {2x + 5} never intersects with {mx}
To that end m=2 (same slope), if so the 2 linear functions:

y = 2x+5 and y = 2x are PARALLEL


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What is the missing reason in the proof? (Reason 9)
den301095 [7]

Answer:

transitive property

Step-by-step explanation:

Generally proofs flow naturally from one step to the next.  Consequently, each step usually follows from the previous step, and the Reason given justifies why that change is valid.

From statement 8, note that 90^{o}=m\angle{ABD}

For statement 9, the proof asserts that m\angle{ABC}=m\angle{ABD}

What changed between line 8 and 9?  The left side of the equation lost it's 90 degrees, and it became the measure of angle ABC.

So, what justifies changing the 90degrees into a measure of an angle (specifically, the measure of angle ABC)?

Recall from statement 3, that m\angle{ABC}=90^{o}.

The "substitution property" would be a valid reason for step 9, (but of the given options, that isn't one, so we must look for another valid reason).


Recall that the transitive property states:

\text{If }a=b\text{ and }b=c, \text{then }a=c

There are three parts,

1. the first part needs a=b

2. the second part needs b=c

3. the third part produces a=c

Notice that in the second part, b=c, and then for the third part, on the left side, the "b" disappears, and the "a" sort of appears out of nowhere.

Statement 8 is like the second part, and statement 9 is like the third part.

Replacing "a" with m\angle{ABC}, replacing "b" with 90^{o}, and replacing "c" with m\angle{ABD}, we can update the transitive property and see how it applies to our situation:

Original transitive property:  \text{If }a=b\text{ and }b=c, \text{then }a=c

Updated transitive property:  \text{If }m\angle{ABC}=90^{o}\text{ and }90^{o}=m\angle{ABD}, \text{then }m\angle{ABC}=m\angle{ABD}

In order to use the transitive property, we need the first part and the second part to be true, and then it will be a valid reason for the last part to be true.  The first part was already proven back in statement 3, the second part was just proven in statement 8, so the conclusion (the third part) is valid and can be statement 9, because of the transitive property.

7 0
1 year ago
Helpppp and explain///////////////////////////
Sveta_85 [38]

Answer:

A

Step-by-step explanation:

The first thing we have to do here is to subtract g(x) from f(x)

We have this as;

2x + 4 -(3x-7)

= 2x + 4-3x + 7

= -x + 11

Now, we substitute the value of x for 5

We have -5+ 11 = 6

8 0
3 years ago
Find the x-intercept and y-intercept f(x)=(x^2-4)(x+1)
iVinArrow [24]
Multiply to get it in standard from, which gives you the y-intercept as the constant.

for x, factor it all the way down and set the factors equal to zero. the answers are the x-intercepts
6 0
3 years ago
write the x and y coordinate (in the second and third column, respectively) of dilation of quadrilateral ABCD with vertices A(1,
gayaneshka [121]

Answer:

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

Step-by-step explanation:

From Linear Algebra, we define dilation by the following equation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

O(x,y) - Center of dilation, dimensionless.

P(x,y) - Original point, dimensionless.

k - Scale factor, dimensionless.

P'(x,y) - Dilated point, dimensionless.

If we know that O(x,y) = (0, 0), k = 2, A(x,y) = (1,1), B(x,y) = (2,2), C(x,y) = (4,1) and D(x,y) = (2,-1), then the dilated points are, respectively:

Point A

A'(x,y) = O(x,y) + k\cdot [A(x,y)-O(x,y)] (2)

A'(x,y) = (0,0) + 2\cdot [(1,1)-(0,0)]

A'(x,y) = (2,2)

Point B

B'(x,y) = O(x,y) + k\cdot [B(x,y)-O(x,y)] (3)

B'(x,y) = (0,0) + 2\cdot [(2,2)-(0,0)]

B'(x,y) = (4,4)

Point C

C'(x,y) = O(x,y) + k\cdot [C(x,y)-O(x,y)]

C'(x,y) = (0,0) + 2\cdot [(4,1)-(0,0)]

C'(x,y) = (8,2)

Point D

D'(x,y) = O(x,y) + k\cdot [D(x,y)-O(x,y)]

D'(x,y) = (0,0) + 2\cdot [(2,-1)-(0,0)]

D'(x,y) = (4,-2)

The coordinates of the dillated vertices are A'(x,y) = (2,2), B'(x,y) = (4,4), C'(x,y) = (8,2) and D'(x,y) = (4,-2).

4 0
3 years ago
What is 8/10 divided by 1 5/6
sveta [45]
1st change 1 5/6 into a mixed number:
1 5/6 = 11/6

New problem:
8/10 divided by 11/6

to divide fractions you turn the 1st fraction upside down and then change the division sign to a multiplication sign:

8/10 / 11/6
10/8 * 11/6
=55/24 or 1 7/24
5 0
3 years ago
Read 2 more answers
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