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lina2011 [118]
3 years ago
8

25% of what number is 30.2? i need help solving.​

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
8 0
120.8. Make a proportion. 25/100 equals 30.2 over x, the number. Now cross multiply. 100 times 30.2 divided by 25, so it is 120.8.

Another way to reason this is to see that 25 percent is one fourth, so just do 30.2 times 4
Verdich [7]3 years ago
4 0

Answer:

Step-by-step explanation:

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∠1 ​ and ∠2 are supplementary. ∠1=124°∠2=(2x+4)° Select from the drop down menu to correctly answer the question.
Alex_Xolod [135]
Remark
Supplementary angles add up to 180o. 

Givens
<1 = 124
<2 = 2x + 4

I imagine you are looking for either x or <2. 

Equation
<1 + <2 = 180          Substitute the givens
124 + 2x + 4 = 180  Collect like terms on the left.
128 + 2x = 180         Subtract 128 from both sides
2x = 180 - 128          Collect like terms on the right   
2x = 52                     divide by 2
x = 52/2
x = 26 <<<<<<<<< answer

<1 = 124
<2 = 2x + 4 = 2*26 + 4
<2 = 52 + 4
<2 = 56  <<<<<<<< answer

We need choices if you want an exact answer.

3 0
3 years ago
2x+1&gt;<br><img src="https://tex.z-dn.net/?f=2x%20%2B%201%20%5Cgeqslant%205%20-%20x" id="TexFormula1" title="2x + 1 \geqslant 5
melisa1 [442]
What are we supposed solve for? Be for specific please
4 0
3 years ago
Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2
LUCKY_DIMON [66]
Make a change of coordinates:

u(x,y)=xy
v(x,y)=\dfrac xy

The Jacobian for this transformation is

\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}

and has a determinant of

\det\mathbf J=-\dfrac{2x}y

Note that we need to use the Jacobian in the other direction; that is, we've computed

\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}

but we need the Jacobian determinant for the reverse transformation (from (x,y) to (u,v). To do this, notice that

\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}

we need to take the reciprocal of the Jacobian above.

The integral then changes to

\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv
=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2
8 0
3 years ago
HELP PLEAAAAAASEEEEEEEE!
Inga [223]

angle 2 is congruent to angle six


8 0
3 years ago
Read 2 more answers
43% of what number is 65
nataly862011 [7]

Answer:

I believe the answer will be around 28

Step-by-step explanation:

Hope this Helped

3 0
2 years ago
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