Using it's concept, it is found that the experimental probability that the first vehicle rented today will be a pickup truck is of 0.5 = 50%.
<h3>What is a probability?</h3>
A probability is given by the<u> number of desired outcomes divided by the number of total outcomes</u>. For an experimental probability, these number of outcomes are taken from previous trials.
In this problem, we have that out of 4 vehicles, 2 are pickup trucks, hence the experimental probability is given by:
p = 2/4 = 1/2 = 0.5.
More can be learned about probabilities at brainly.com/question/14398287
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Answer:
a,c,e,f
Step-by-step explanation:
scientific notations can only be less than 9
Answer:
First we need to name some of the variables we are given:n = 38 the sample sizex = 6.88 the sample mean = 1.86 the population standard deviationWe need to find a 90% confidence interval for the mean price per 100 lbs of watermelon: = 1-.90 = .10/2 = .05z(/2) = -1.64-z(/2) = 1.64This can give us a probability expression:P(-1.645 < z < 1.645) = .90The margin of error is calculated with the formula: E = z(/2)(/√n)E = 1.645(1.86/√38) = $.4963(300) = $148.89 Then to calculate the upper and lower limit we add and subtract E from x:lower limit = 6.88 - .4963 = $7.38(300) = $2214upper limit = 6.88 + .4963 = $6.38(300) = $1914Note: We multiply the E, upper and lower limits by 300 because 15 tons is 30000lbs and we need the price per 100 lbs, so we divide 30000/100 and get 300.
Step-by-step explanation:
Answer:
0.0035289
Step-by-step explanation:
From the question;
mean annual salary = $63,500
n = sample size = 31
Standard deviation = $6,200
Firstly, we calculate the z-score of $60,500
Mathematically;
z-score = x-mean/SD/√n = (60500-63500)/6200/√(31) = -2.6941
So we want to find the probability that P(z < -2.6941)
We can get this from the standard normal table
P( z < -2.6941) = 0.0035289
Answer:
3.73
Step-by-step explanation:
56/15
3 11/15
3.73
