Answer:
The answer is 8 years
Explanation:
FV= PV(1+r)^n
Where
PV= let's assume PV is $100
FV = Since FV will be doubled, the we have $200($100 x 2)
n= ?
r= 9percent
Let us use the rule of 72 which states that an investment will double when:
Annual Investment Rate x Number of Years = 72.
Number of years = 72/9
= 8 years
The investment is doubled in 8 years at the rate of 9percent
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Answer:
The correct answer is: Service Quality Gap.
Explanation:
The Service Quality Gap refers to the difference between what a company understands a customer's desires and what must be really done to satisfy that consumer. Firms should make all the efforts in their hands to close that breach and provide the customer with the good or service they need to keep their businesses going. When the gap is not closed, the customer's loyalty fails, pushing them to look for different options in other organizations.
Answer: a. $73,810.88
b. $10,185.18
Explanation:
a. The payments of $11,000 are constant so this can be considered an Annuity.
The cost of the Computer is it's present value which is,
Present Value of Annuity = Annuity Payment * Present Value Interest Factor of Annuity, 11%, 10 periods
= 11,000 * 6.71008 (Payment is made at the end of the year so this is an Ordinary Annuity)
= $73,810.88
b. When an Annuity is instead paid at the beginning of the period it is considered to be an Annuity due.
The formula is the same but for the figures ,
Present Value of Annuity Due = Annuity * Present Value Interest Factor of an Annuity Due, 11% , 10 periods
73,810.88 = Annuity * 7.24689
Annuity = 73,810.88/7.24689
= $10,185.18
Answer:
Expected return is: 7.37% and the Standard deviation is: 24.96%
Explanation:
Correlation between fund S&B=0,0667
Standard Deviation of Fund S=41%
Standard Deviation of Fund(B)=30%
E(R) of Stock Fund S=12%
E(R) of Stock Fund B=5%
Covariance between the funds = Standard Deviation of Fund(B) × Standard Deviation of Fund S × correlation between these funds
Cov = 0.41 × 0.30 × 0.0667 = 0.008204
Now minimum variance portfolio is found by applying:
W min(S)=(SDB)^2-Cov(B,S) / ((SDS)^2+(SDB)^2-2Cov(B,S)
W min(S) = 0.338431
W min(B) = 1-0.338431=0.661569
1) E(r)min= 0.338431 × 12% + 0.661569 × 5% = 7.37%
2) Standard Deviation:
SD Min = (Ws^2XSDs^2+Wb^2XSDb^2+2XWsWb*Cov(s,B)^1/2
SDmin=(0.338431^2 × 0.41^2 + 0.661569^2 × 0.3^2 + 2 × 0.338431 × 0.661569 × 0.008204)^1/2
SDmin=24.96%