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Verdich [7]
3 years ago
7

Which number in the monomial 125x^18y^3z^25 needs to be changed to make it a perfect cube

Mathematics
2 answers:
USPshnik [31]3 years ago
6 0

Answer:

The required number in teh polynomial needs to be changes to make it a perfect cube is z^{25} .

Step-by-step explanation:

Given : Expression  125x^{18}y^3z^{25}

To find : Which number in the monomial expression needs to be changed to make it a perfect cube?

Solution :

Expression  125x^{18}y^3z^{25}

Using property,

(x^a)^b=x^{ab} and (xy)^a=x^ay^a

Now we distribute each term into a power cube.

125=5^3

x^{18}=x^{3\cdot 6}

y^{3}=y^{3\cdot 1}

z^{25}=z^{3\cdot 8+1}

We have seen that

z^{25} is not making a multiple of 3 so to make it a perfect cube we have to change it into z^{24}=Z^{3\cdot 8}

Now, Making a perfect cube with the change

125x^{18}y^3z^{25}

=5^3x^{3\cdot 6}y^{3\cdot 1}z^{3\cdot 8}

=(5)^3(x^{6})^3(y)^{3}(z^8)^3

=(5x^6yz^8)^3

Therefore, The required number in teh polynomial needs to be changes to make it a perfect cube is z^{25} .

Oksana_A [137]3 years ago
4 0

Hi,

You just have to change z^25 to z^24 or z^27.

125x^{18}y^3z^{24}=(5x^6*y*z^8)^3

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