Since a $5 decrease in price increases customers by 20 we can say that we have two points:
(125,100) and (120,120), from these we can find the slope or rate of change of customers as a function of price...
m=20/-5
m=-4
m=-4
c(p)=-4p+b, now we can use (125,100) to solve for b
100=-4(125)+b
100=-500+b
600=b, so our number of customers as a function of price is:
c(p)=600-4p
Revenue will simply be the number of customers times the price charged per customer...or p*c(p):
r(p)=600p-4p^2
We can find price that creates maximum revenue by finding when the derivative is equal to zero...
dr/dp=600-8p
dr/dp=0 only when
0=600-8p
8p=600
p=75
So the price that maximizes revenue is $75.
Answer:
x=-2
Step-by-step explanation:
5^(9-6)=125
5^3=125
Recall that (a+b)²=a²+2ab+b²
100x²+120x+z
in this case, because100x²=(10x)², a=10x, z=b²
120=2*10*b
b=6
z=b²=36
the square is (10x+6)²
The common factor is 7 so its
7(2x - 3)
We know that
the addition rule states that
P(A or B) = P(A) + P(B) − P(A and B)
in this problem
P(A)=0.72
P(B)=0.84
P(A and B)=0.64
so
P(A or B) = P(A) + P(B) − P(A and B)-----> 0.72+0.84-0.64
P(A or B) = 0.92
the answer is
0.92 (92%)