Answer:
-25
Step-by-step explanation:
Evaluate -x - 6 x + 10 where x = 5:
-x - 6 x + 10 = -5 - 6×5 + 10
-6×5 = -30:
-5 + -30 + 10
-5 - 30 + 10 = 10 - (5 + 30):
10 - (5 + 30)
5 + 30 = 35:
10 - 35
10 - 35 = -(35 - 10):
-(35 - 10)
| 3 | 5
- | 1 | 0
| 2 | 5:
Answer: -25
Answer:
c
Step-by-step explanation:
Answer:
94.8
Step-by-step explanation:
94.8 is the answer for 1st q
Answer:
y = -3x +10 Step-by-step explanation:
y+2 = -3(x-4)
y+2 = (-3*x) + (-3*-4)
y+2 = -3x + 12
^ -2 = . ^ -2
y = -3x +10
First off, let's convert the decimal to a fraction, notice, we have two decimals, so we'll use in the denominator, a 1 with two zeros then, two decimals, two zeros, thus
![\bf 1.\underline{75}\implies \cfrac{175}{1\underline{00}}\implies \cfrac{7}{4}\implies \stackrel{ratio}{7:4}](https://tex.z-dn.net/?f=%5Cbf%201.%5Cunderline%7B75%7D%5Cimplies%20%5Ccfrac%7B175%7D%7B1%5Cunderline%7B00%7D%7D%5Cimplies%20%5Ccfrac%7B7%7D%7B4%7D%5Cimplies%20%5Cstackrel%7Bratio%7D%7B7%3A4%7D)
now, we know then the ratio dimensions for the new photograph,
![\bf \qquad \qquad \textit{ratio relations} \\\\ \begin{array}{ccccllll} &\stackrel{ratio~of~the}{Sides}&\stackrel{ratio~of~the}{Areas}&\stackrel{ratio~of~the}{Volumes}\\ &-----&-----&-----\\ \cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3} \end{array} \\\\ -----------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20%5Cqquad%20%5Cqquad%20%5Ctextit%7Bratio%20relations%7D%0A%5C%5C%5C%5C%0A%5Cbegin%7Barray%7D%7Bccccllll%7D%0A%26%5Cstackrel%7Bratio~of~the%7D%7BSides%7D%26%5Cstackrel%7Bratio~of~the%7D%7BAreas%7D%26%5Cstackrel%7Bratio~of~the%7D%7BVolumes%7D%5C%5C%0A%26-----%26-----%26-----%5C%5C%0A%5Ccfrac%7B%5Ctextit%7Bsimilar%20shape%7D%7D%7B%5Ctextit%7Bsimilar%20shape%7D%7D%26%5Ccfrac%7Bs%7D%7Bs%7D%26%5Ccfrac%7Bs%5E2%7D%7Bs%5E2%7D%26%5Ccfrac%7Bs%5E3%7D%7Bs%5E3%7D%0A%5Cend%7Barray%7D%20%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C)