Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>
Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer:
f(1) = 4; f(n) = 4 + d(n - 1), n > 0.
Step-by-step explanation:
This arithmetic sequence has a common difference of d with first term = 4.
f(1) = 4; f(n) = 4 + d(n - 1), n > 0.
The answer is y=0
See the attached photo for details
Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.
Answer:
Don't spin the barrel.
Step-by-step explanation:
Each time you spin the barrel, the probability A of finding a bullet, having two bullets in six chambers is:
For you to get shot in the second try but not the first, the barrel spin would have to stop precisely at one specific chamber: the one right before the bullets, so that probability would be:
which means that this event is half as likely as finding a bullet every time the barrel is spun. Your chances are better if you pull the trigger for the second time without spinning the barrel.
$71.98 is the total cost for the meal
59.00
+ 4.13
+ 8.85
======
71.98
