550 sq m
Step-by-step explanation:
Step 1 :
The length of the first cross road the park is 70 m
The width of the first cross road the park is 5 m
So its area is 70 * 5 = 350 sq m
Step 2 :
The length of the second cross road the park is 45 m
The width of the width cross road the park is 5 m
So its area is 45 * 5 = 225 sq m
Step 3 :
The 2 cross roads intersect in the middle at an area of 5 * 5 = 25 sq m
This area is included in the computation of the area of both the cross roads and hence we need to subtract this area from the sum of the area of both the cross roads to obtain the actual area of cross roads in the park
So we have
the area of the cross roads inside the park = 350 + 225 - 25 = 550 sq m
4x7=28
6x2=12
3-28+7-12
-25+7-12
-25+(-5)
(-30)
Answer:
Survey
Step-by-step explanation:
It’s hard to tell because there isn’t a visual. My guess is that it’s ASA~ and SAS~ because T is congruent to P and A and F have the same angle
Hi there!
<u><em>FACT</em></u><em>:</em>
<em>What you have there is an equilateral in which all three internal angles are congruent to each other and are each 60°.</em>
<u>STEPS TO ANSWER:</u>
I'm not really sure if you are looking for the value of "X" the angle or the value of "x" that is part of the expression that represents the value of the angle "Z".
1. If you are looking for the value of "X" the angle, it's pretty easy knowing that all internal angles are equal to 60°.
Your answer for the value of "X" the angle would be : X = 60°.
2. If you are looking for the value of the "x" that is part of the expression that represents the value of the angle "Z", you'll need to write this expression as equal to 60 and solve the equation by isolating "x" :
2x <u>- 4</u> = 60
Add 4 on each side of the equation → 60 + 4 = 64
<u>2</u>x = 64
Divide each side of the equation by 2 → 64 ÷ 2 = 32
x = 32
Your answer for the value of the "x" that is part of the expression that represents the value of the angle "Z" would be : x = 32.
There you go! I really hope this helped, if there's anything just let me know! :)
