Answer:
4/(√7 + √3)
Step-by-step explanation:
=> Multiply and divide by (√7-√3)
=> 4(√7 - √3)/((√7 + √3)(√7 - √3)
=> 4(√7 - √3)/((√7)² - (√3)²)
=> 4(√7 - √3)/((7) - (3))
=> 4(√7 - √3)/4
=> √7 - √3
Answer:
In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given:
Original price of the ticket is 
Price after using the coupon is 
Coupon discount is 85% of 
Therefore, the price after applying coupon is given as the difference of the original price and the coupon discount. That is,
The graph is shown below. The graph passes through the origin as the above relationship is a proportional relationship.
The line strictly remains in the first quadrant as both and can't be negative as they represent price of tickets and price can never have negative values. Hence, only the first quadrant has both the values of and positive.
Answer:
AD BC only
Step-by-step explanation:
