Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp
h and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?
A:230
B:250
C:210
1 answer:
Answer:
C. 210 miles.
Step-by-step explanation:
If Car 1 left 30 minutes earlier
than Car 2 therefore Car 2 traveled 3 hours
compared to Car 1's 3.5 hours
Car 1 traveled 3.5 x 42 mph = 147 miles
Car 2 travelled 3 x 50 mph = 150 miles
The distance between them would be
√147^2 + 150^2
= 210
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