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jeyben [28]
3 years ago
8

Two cars leave Phoenix and travel along roads 90 degrees apart. If Car 1 leaves 30 minutes earlier than Car 2 and averages 42 mp

h and if Car 2 averages 50 mph, how far apart will they be after Car 1 has traveled 3.5 hours?
A:230
B:250
C:210
Mathematics
1 answer:
beks73 [17]3 years ago
8 0

Answer:

C. 210 miles.

Step-by-step explanation:

If Car 1 left 30 minutes earlier

than Car 2 therefore Car 2 traveled 3 hours

compared to Car 1's 3.5 hours

Car 1 traveled 3.5 x 42 mph = 147 miles

Car 2 travelled 3 x 50 mph = 150 miles

The distance between them would be  

√147^2 + 150^2

= 210

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sergij07 [2.7K]
This is a compound interest problem, therefore s(t) should be in the form:
s(t) = a(r)^{t}

where: 
t = time in years
s(t) = the value of your item after t years
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r = rate

Therefore, we already know that a = 245$.

Now, we can calculate r:
r^{t}=\frac{s}{a}
r =  \sqrt[t]{ \frac{s}{a} }
r = \sqrt[5]{ \frac{560.50}{245} }
     = 1.18

Therefore, the correct answers are a = 245 and r = 1.18

4 0
3 years ago
A stick of butter measures 3 cm wide, 8 cm long, and 2 cm high. What is the volume of the stick of butter?
Jobisdone [24]

Answer:

48cm

Step-by-step explanation:

V= L x W x H

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5 0
2 years ago
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Sloan [31]
So than you check this graph so you see that the radius has a length of 4 units 
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2 years ago
If 2k, 5k-1 and 6k+2 are the first 3 terms of an arithmetic sequence, find k and the 8th term​
Klio2033 [76]

Answer:

see explanation

Step-by-step explanation:

The common difference d of an arithmetic sequence is

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Substitute in values and solve for k, that is

5k - 1 - 2k = 6k + 2 - (5k - 1)

3k - 1 = 6k + 2 - 5k + 1

3k - 1 = k + 3 ( subtract k from both sides )

2k - 1 = 3 ( add 1 to both sides )

2k = 4 ⇒ k = 2

--------------------------------------------------------

The n th term of an arithmetic sequence is

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a_{1} = 2k = 2 × 2 = 4 and

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3 years ago
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Answer:

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Step-by-step explanation:

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