In ΔDEF, d = 440 inches, f = 410 inches and ∠F=120°. Find all possible values of ∠D, to the nearest 10th of a degree.

Mathematics

1 answer:

aliya0001 [1]3 years ago

3 0

Answer:

In AMNO, n = 92 inches, N=119° and 20=20°. Find the length of m, to the nearest 10th of an inch In AJKL, j = 9.6 inches, k = 6.4 inches and I=8.4 inches. Find the measure of K to thelaearest degree. In AQRS. q = 49 cm, 7.1 cm and S=70°. Find the area of AQRS, to the nearest 10th of a square centimeter Find all angles, 0 = 0 < 360°, that satisfy the equation below, to the nearest 10th of a degree. 25 sino-1=0 Find all angles, 0 SC <360°, that satisfy the equation below, to the nearest tenth of a degree (if necessary). 12 sin C + 6 = 5 sin ( + 6

Step-by-step explanation:

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For all values of x, f(x) = x^2 + 3x and g(x) = x - 4 Show that fg(x) = x^2 - 5x + 4

Westkost [7]

Answer:

f(g(x)) = x² - 5x +4

Step-by-step explanation:

Explanation

Given that the functions

f(x) = x² + 3 x and g(x) = x-4

f(g(x)) = f(x -4) (∵ g(x) = x-4)

= (x-4)² + 3(x-4)

= x² - 2(4)x + 4² + 3x -12

= x² - 8 x + 16 + 3x -12

= x² - 5x +4

∴ f(g(x)) = x² - 5x +4

4 0

3 years ago

Use the Remainder Theorem to find the remainder when P(x) = x^4 – 9x^3 – 5x^2 – 3x + 4 is divided by x + 3.

kirza4 [7]

P(x) = (x + 3)Q(x) + R

 P(-3) = (0)Q(x) + R 

i P(-3) = R 

Now, P(-3) = (-3)⁴ - 9(-3)³ - 5(-3)² - 3(-3) + 4
So

P(-3) = 81 + 243 - 45 + 9 + 4 
=. 292
hope it helps

6 0

3 years ago

Read 2 more answers

Pleas help me find the answer and show the work to this question

lions [1.4K]

Answer:

$Leg\ 1 = 8$