All categories

3 years ago

Evaluate the function for g(-2). g(x) = -4x^3 + 8x - 14

Mathematics

1 answer:

baherus [9]3 years ago

7 0

The answer is >>> g(0)=-14

You might be interested in

Which of the following statements is true about the three quadrilaterals? (5 points)

klemol [59]

Answer:

1 one os true

2 nd one is true

7 0

3 years ago

Evaluate each expression if a = 6, b = 3, and c = 2.

earnstyle [38]

Answer:

a = 6, b = 3, and c = 2

1. ab1 = 6 × 3 × 1 = 18

2. c + 42 = 2 + 42 = 44

3. 18 = 18

4. a − b4 = 6 - 3(4) = 6 - 12 = - 6

5. 2c3 = 2 × 2 × 3 = 12

6. b ÷ 35 = 3÷35 = 0.086

7. a − 1 6 = 6 - 16 = -10

8. 6 + c8 = 6 + 2 (8) = 6 + 16 = 22

Step-by-step explanation:

7 0

3 years ago

The equation and graph of a polynomial are shown below. The graph reachesits minimum when the value ofx is 4. What is the y valu

olga_2 [115]

The y-value of this minimum is 4 .

6 0

3 years ago

Find the measure of the missing angles. (Picture Below)

Alenkasestr [34]

Answer:

b. 119

c. 119

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Step-by-step explanation:

Given functions:

$p(x)=2x-4$

$r(x)=\dfrac{6x-1}{9x+1}$

Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

brainly.com/question/27750885

brainly.com/question/27739892

6 0

2 years ago

Evaluate the function for g(-2). g(x) = -4x^3 + 8x - 1￼4

Evaluate the function for g(-2). g(x) = -4x^3 + 8x - 14