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Ray Of Light [21]
4 years ago
10

What is the equation of this line? y=32x y=−32x y=−23x y=23x

Mathematics
2 answers:
Anni [7]4 years ago
8 0
-32x I am sure 
I hope it works i was not actually sure
NARA [144]4 years ago
7 0

Answer:

y= 2/3x

Step-by-step explanation:

i took the test

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30 POINTS! Combine the like terms of the 2 questions below:
astraxan [27]

Answer:

\tt 1)\: \boxed{\tt 4y+10}

\tt 2)\:\boxed{\tt 0.5x^4+10.5}

Step-by-step explanation:

1) y + 4 + 3(y + 2)

Expand:-

\tt y+4+3y+6

Combine like terms:-

\tt y+3y+4+6

\boxed{\tt 4y+10}

__

2) 0.5(x⁴ - 3) + 12

Expand:-

\tt 0.5x^4-1.5+12

Add/Subtract Numbers:-

\boxed{\tt 0.5x^4+10.5}

___________________

5 0
2 years ago
Please Help.
Bond [772]
5 x 6 + 7? Is that what the answer is, I didn't get the question towards the end. :)
6 0
3 years ago
Read 2 more answers
4. Polynomial Division<br> Divide. (x3 – 2x – 3) ÷ (x + 3)
lys-0071 [83]
The answer would be 24/x+3 in Polynomial Division :-)
4 0
4 years ago
A rectangle has length 72 cm and width 56 cm. The other rectangle has the same area as this one, but its width is 21 cm. What is
Ira Lisetskai [31]

The length of the rectangle is = 72 cm

The width of the rectangle is = 56 cm

Area of the rectangle is = length*width

= 72\times56=4032 cm²

As given, the other rectangle has the same area as this one, but its width is 21 cm.

Let the length here be = x

4032=x*21

x=\frac{4032}{21}=192

Hence, length is 192 cm.

We can see that as width decreases, the length increases if area is constant and when length decreases then width increases if area is constant.

So, in the new rectangle,constant of variation=k is given by,

\frac{192}{72}=\frac{8}{3} or \frac{56}{21}=\frac{8}{3}

Hence, the constant of variation is \frac{8}{3}

7 0
3 years ago
2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation whic
Artemon [7]
<h2><u>Problem Solving</u>:-</h2>

2. The table below shows that the distance d varies directly as the time t. Find the constant of variation and the equation which describes the relation.

<h2><u>Solution</u>:-</h2>

Since the distance d varies directly as the time t, then d = kt.

Using one of the pairs of values, (2, 20), from the table, substitute the values of d and t in d = kt and solve for k.

\sf{\rightarrow{d =  kt}}

\sf\rightarrow{20  = 2k }

\sf\rightarrow{K= \frac{20}{2} }

\sf\rightarrow{K={\color{magenta}{10}}}

<h2><u>Answer</u>:-</h2>
  • Therefore, the constant of variation is 10.
3 0
3 years ago
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