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tino4ka555 [31]
3 years ago
7

The sum of four consecutive integers is 74. What is the first integer?

Mathematics
1 answer:
Drupady [299]3 years ago
7 0

Answer:

17

Step-by-step explanation:

Let x, x +1, x + 2, x + 3 be four consecutive integers.

\therefore \: x + x +1 +  x + 2 +  x + 3 = 74 \\  \therefore \: 4x + 6 = 74 \\  \therefore \: 4x = 74 - 6 \\  \therefore \: 4x = 68 \\  \therefore \: x =  \frac{68}{4}  \\  \huge \red{ \boxed{x = 17}}

Hence, first integer is 17.

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33 = 88x
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3(x+2)=−5−2(x−3)
tia_tia [17]

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Step-by-step explanation:

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Step-by-step explanation:

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Read 2 more answers
Ques 1 : x + 1 3/8 = 2 1/4
lapo4ka [179]

Answer:   1. 29/8

                2. 37.72

                3. 24

Step-by-step explanation:

1. x + 1 3/8 = 2 1/4

              x = 21/4 - 13/8

              x = 42/8 - 13/8           [set the denominator equal]

              x = 29/8

2. 13.27 = t - 24.45

Rewrite the function as t - 24.45 = 13.27

                                                   t  = 13.27 + 24.45

                                                   t  = 37.72              

3.  9 = 3/8 × y

Rewrite as 3/8 x y = 9

                            y = 9/ (3/8)

                            y = 9 x (8/3)

                            y = 24

 

6 0
3 years ago
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