Assume:
Size of sides = x m
Depth of the pool = y m
Therefore, surface area = x^2+4xy =10 m^2
Then, y = (10-x^2)/(4x)
Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m
Therefore,
V= 1.826^2*0.913 = 3.044 m^3
Answer:
9 7/8 - ( -2 4/5 - 1/2) = 13.175
Step-by-step explanation:
Hope this is correct and helps.
Answer:
2
Step-by-step explanation:
1. go to desmos Graphing calculator and select graphing calculator
2. Next type in the word length then it should look like this Length
3. Don't space just put this ( and type in the point it should look like this Length(-2,-3),(4,4)
4. Be sure to do double () it should look like this Length((-2,-3),(4,4))
5. It should give you your answer
Break down the words into an equation:
(x+7)/(x+3) + (x-4)/3
Step-by-step explanation:
The formula is Distance=√(x2-x1)²+(y2 -y1)²
x1 is 5, x2 is 1, y1 is 9, y2 is 6
D = √( 1-5)² +(6-9)²
D = √(-4)²+(-3)²
D = √16+9
D = √25
D = 5 units
