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MrMuchimi
3 years ago
8

PLEASE HELP ASAP 25 POINTS

Mathematics
2 answers:
dimaraw [331]3 years ago
4 0

Answer:

the answer is d

Step-by-step explanation:


Tresset [83]3 years ago
4 0

Answer:

d

Step-by-step explanation:

To see if it is a solution substitute x in and see if it works for y

a.  y>= x +2

-4 >= -2+2

-y> = 0 No


b y <= x+2

  -4<=-2+2

-4 <0  True

keep going

y<= x-3

-4 <= -2-3

-4<=-5

No


c  y> x+2

  -4 >-2+2

-4 > 0

True

y< x-3

-4 <-2-3

-4 <-5

NO


d y <= x+2

-4 <= -2+2

-4<=0

True

-4 >= -2-3

-4>=-5


This is the solution

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Answer:

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Step-by-step explanation:

Denote the events as follows:

<em>R</em> = reported case of rabies is a raccoon

<em>F</em> = reported case of rabies is a fox

<em>B</em> = reported case of rabies is a bat

<em>O</em> = reported case of rabies is a some other animal.

The data provided is:

P (R) = 0.55

P (F) = 0.11

P (B) = 0.04

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(a)

A property of a probability distribution is that the sum of all individual properties is 1.

That is, \sum P(X)=1

Compute the value of <em>x</em> as follows:

\sum P(X)=1\\P(R)+P(F)+P(B)+P(O)=1\\0.55+0.11+0.04+x=1\\0.70+x=1\\x=1-0.70\\x=0.30

Thus, the value of <em>x</em> is 0.30.

(b)

The probability of the complement of an event is the probability of its not happening.

P(A^{c})=1-P(A)

Compute the probability that a reported case of rabies is not a raccoon as follows:

P(R^{c})=1-P(R)\\=1-0.55\\=0.45

Thus, the probability that a reported case of rabies is not a raccoon is 0.45.

(c)

Compute the probability that a reported case of rabies is either a bat or a fox as follows:

P(B\cup F)=P(B)+P(F)\\=0.11+0.04\\=0.15

Thus, the probability that a reported case of rabies is either a bat or a fox is 0.15.

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Answer:

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Step-by-step explanation:

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Answer:

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