Answer:
9 inches.
Step-by-step explanation:
Fun question! The length of a space diagonal for a cube is ![\sqrt{3*sidelength^2}](https://tex.z-dn.net/?f=%5Csqrt%7B3%2Asidelength%5E2%7D)
Thus, the first cube has a side diagonal of ![\sqrt{3}](https://tex.z-dn.net/?f=%5Csqrt%7B3%7D)
The next cube would have a side diagonal of 3
The third cube would have a side diagonal of ![3\sqrt{3}](https://tex.z-dn.net/?f=3%5Csqrt%7B3%7D)
And the fourth cube would have a side diagonal of 9.
Since the fifth cube has a side length equal to the side diagonal of the fourth cube, it should be 9 inches.
Answer:
8/3 or 2 2/3
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Group the 4 terms into groups of 2 without changing their order. That looks like this:
![(2x^3+6x^2)+(5x+15)](https://tex.z-dn.net/?f=%282x%5E3%2B6x%5E2%29%2B%285x%2B15%29)
Now within each group pull out what's common:
![2x^2(x+3)+5(x+3)](https://tex.z-dn.net/?f=2x%5E2%28x%2B3%29%2B5%28x%2B3%29)
Now we have (x + 3) common between the 2 terms, so let's pull that out. With grouping, you know that it "works" if what's in the parenthesis are both exactly the same term. Ours are both (x + 3). What's "left over" are the things we originally pulled out, so group those together and you're done!
![(x+3)(2x^2+5)](https://tex.z-dn.net/?f=%28x%2B3%29%282x%5E2%2B5%29)
To answer this, the first step is to divide 6.55 by 5
6.55/5 = 1.31
1.31 is the cost of one marker
Now multiply 1.31 by 4 to get the cost of 4 markers
1.31 × 4 = 5.24
4 markers are $5.24
Backtracking we see that the answer that best represents this is D.<span />