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Dmitry [639]
4 years ago
8

In about 5 billion years, at the end of its lifetime, our sun will end up as a white dwarf, having about the same mass as it doe

s now, but reduced to about 15,000 km in diameter. What will be its density at that stage? In g/cm^3

Physics
2 answers:
masya89 [10]4 years ago
8 0
The formula of density is given by

Density = Mass ÷ Volume

We have:
Mass = 1.989 × 10³⁰ kg
Volume = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (7500)^3 = 1.767*10^12 km³

Density = \frac{(1.989)(10^{30})}{(1.767)(10^{12})}=1.13×10¹⁸ kg/km³

Converting 1.13 × 10¹⁸ kg/km³ to g/cm³

1.13 × 10¹⁸ kg = 1.13 × 10¹⁸ × 10³ = 1.13 × 10²¹ grams
1 km³ = 1 × 10⁶ cm³ 

(1.13 × 10²¹) ÷ 10⁶ = 1.13 × 10¹⁵ gr/cm³

Answer: Density 1.13 × 10¹⁵ gr/cm³
Hitman42 [59]4 years ago
8 0

1.125 x 10⁶ g/cm³.

<h3>Further explanation </h3>

<u>Given: </u>

  • The mass of the sun = 1.989 x 10³⁰ kg
  • The final diameter of the sun = 15,000 km

<u>Question:  </u>

What will represent the density of our sun at the end of its lifetime? (in g/cm³)

<u>The Process:  </u>

In the beginning, we calculate the volume of our sun which will end up like a white dwarf.

Let's assume the sun as a perfect sphere.  

Prepare the radius, i.e., \boxed{ \ R = \frac{1}{2} \times diameter \ }

\boxed{ \ R = \frac{1}{2} \times 15,000 \ km \ } \rightarrow \boxed{ \ 7,500 \ km \ }

Volume of sphere \boxed{ \ V = \frac{4}{3} \pi R^3 \ }

\boxed{ \ V = \frac{4}{3} \pi (7,500)^3 \ }

We deliver the volume of the sun at the stage, i.e., \boxed{ \ V = 1.767 \times 10^{12} \ km^3 \ }

Let us convert km³ to cm³ by multiplying \boxed{ \ (10^3)^5 \rightarrow 10^{15} \ }

\boxed{ \ V = 1.767 \times 10^{12} \times 10^{15} \ cm^3 \ } \rightarrow \boxed{ \ V = 1.767 \times 10^{27} \ cm^3} \ } \ }[/tex]

After preparing the volume, then we proceed with calculating its density. The formula of density is provided by \boxed{ \ Density = \frac{mass}{volume} \ }

\boxed{ \ Density = \frac{1.989 x 10^{30} \ kg}{1.767 \times 10^{27} \ cm^3} \ }

Let us convert kg to gram by multiplying 10³.

\boxed{ \ Density = \frac{1.989 x 10^{33} \ g}{1.767 \times 10^{27} \ cm^3} \ }

Thus, the density of our sun at the end of its lifetime approximately will be \boxed{\boxed{ \ 1.125 \times 10^6 \ g/cm^3 \ }}  

<h3>Learn more </h3>
  1. About the mass and density of substances  brainly.com/question/4053884
  2. The energy density of the stored energy  brainly.com/question/9617400
  3. The theoretical density of platinum which has the FCC crystal structure brainly.com/question/5048216

<u>Keywords:</u> density, our sun will end up as a white dwarf, reduced to about 15,000 km in diameter, mass, volume of the sphere, in about 5 billion years, at the end of its lifetime

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