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3 years ago

How can a vector have a component value equal to zero and also have a non zero magnitude

1 answer:

lina2011 [118]3 years ago

5 0

The vector's magnitude is the square root of (one component squared) + (the other component squred). The magnitude is non-zero if one component or the other is zero, but not if they both are.

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A mass of 5 kg stretches a spring 20 cm. The mass is acted on by an external force of 10 sin t 6 N (newtons) and moves in a medi

nordsb [41]

Answer:

u" + 40u' + 49u = 2 sin(t/6)

upp + 40up + 49u = 2 sin(t/6)

Explanation:

Step 1: Data given

mass = 5 kg

L = 20 cm = 0.2 m

F = 10 sin(t/6)N

Fd(t) = - 6 N

u(0) = 0.03 m/s

u(0) = 0

u'(0) = 3 cm/s

Step 2:

ω =kL

k = ω/L = m*g /L = (5*9.8)/0.2 = 245 kg/s²

Since Fd(t) = -γu'(t) we know:

γ =- Fd(t) / u'(t) = 6N/ 0.03 m/s = 200 Ns/m

The initial value problem which describes the motion of the mass is given by

5u" + 200u' + 245u = 10 sin(t/6) u(0) = 0 ; u'(0) = 0.03

This is equivalent to:

u" + 40u' + 49u = 2 sin(t/6) u(0) = 0 ; u'(0) = 0.03

upp + 40up + 49u = 2 sin(t/6)

With u in m and t in s

5 0

4 years ago

Which terms describe the motion of most objects in our solar system?

olga2289 [7]

Answer:Geography, Earth Science, Astronomy

Rotation describes the circular motion of an object around its center.

Explanation:

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3 years ago

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Hi i do not have a question i just want to show u my cute doggo :)) ik everyone on here is probably stressed so hope this makes

Arisa [49]

Answer:

wooowwwwww

Explanation:

it's so so cuteeeeeeee

I love dogs tho:))

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3 years ago

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Consider the rocket in the image. Which unbalanced force accounts for the direction of the net force of the rocket ?

Wittaler [7]

Answer:

unbalenced force

Explanation:

make Brainliest plz

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3 years ago

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The magnetic field produced by a long straight current-carrying wire is

alexdok [17]

Answer:

proportional to the current in the wire and inversely proportional to the distance from the wire.

Explanation:

The magnetic field produced by a long, straight current-carrying wire is given by:

$B=\frac{\mu_0 I}{2 \pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current intensity in the wire

r is the distance from the wire

From the formula, we notice that:

- The magnitude of the magnetic field is directly proportional to I, the current

- The magnitude of the magnetic field is inversely proportional to the distance from the wire, r

Therefore, correct option is

proportional to the current in the wire and inversely proportional to the distance from the wire.

8 0

3 years ago