How many seasons are there in a year

Which phrase describes an electromagnetic wave

Viefleur [7K]

Answer:

a transverse wave consisting of changing electric fields and changing magnetic fields.

Explanation:

An electromagnetic wave is a wave generated by the vibration of perpendicular electric and magnetic fields, which may progate through vacuum (empty space) or a material medium.

All electromagnetic waves propagate at the same speed in vacuum. This speed is approximately 3.0 × 10⁸ m/s. Which is generally referred as the speed of light, but it is the same constant speed of any electromagnetic wave in the vacuum, c.

In general, waves transfer energy when they travel, but only electromagnetic waves can travel in vacuum. The waves that cannot travel in vacuum are named mechanical waves (they need a medium to travel).

There are two types of waves depending on how they propagate: transverse waves and longitudinal waves. The transverse waves travel perperdiculary to the direcction of the vibration, while longitudinal waves travel parallel to the direction of the vibration.

The classical example of transverse waves is a rope that oscilates up and down. The classical example of longitudinal waves is a spring that you pull and push by an end and so it moves forward and back. Sound is also a longitudinal wave.

4 0

2 years ago

A tennis player receives a shot with the ball (0.0600 kg) traveling horizontally at 50.4 m/s and returns the shot with the ball

jonny [76]

(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s

(b) The work that the racket does on the ball is -35.1 Joule

<h3>Further Explanation</h3>

Given :

mass of ball = m = 0.06 kg

initial velocity = v₁ = -50.4 m/s

final velocity = v₂ = 37.0 m/s

Unknown :

(a) Impulse = I = ?

(b) Work = W = ?

Solution :

<h2>Question (a) :</h2>

In this question , we could use the formula from Second Law of Newton :

$I = \Delta p$

$I = p_2 - p_1$

$I = m \times v_2 - m \times v_1$

$I = m \times (v_2 - v_1)$

$I = 0.06 \times (37.0 - (-50.4))$

$I = 0.06 \times (87.4)$

$I = 5.244~kg.m/s$

$\large { \boxed {I \approx 5.24~kg.m/s} }$

<h2>Question (b) :</h2>

$W = F \times d$

$W = (\frac{I}{\Delta t})(\frac {v_1 + v_2}{2} \Delta t)$

$W = \frac{I(v_1 + v_2)}{2}$

$W = \frac{5.244(-50.4 + 37)}{2}$

$W = \frac{5.244(-13.4)}{2}$

$W = -35.1348~Joule$

$\large { \boxed {W \approx -35.1~Joule}}$

<h3>Learn more</h3>

Newton's Law of Motion: brainly.com/question/10431582

Example of Newton's Law: brainly.com/question/498822

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Dynamics

Keywords: Newton, Law, Impulse, Work

6 0

4 years ago

A golfer hits a golf ball at an angle of 25 degrees to the ground at a speed of 76 m/s. If the gold ball covers a horizontal dis

Lady bird [3.3K]

The ball's horizontal position x and vertical position y at time t are given by

x = (76 m/s) cos(25º) t

y = (76 m/s) sin(25º) t - 1/2 g t²

where g = 9.80 m/s² is the magnitude of the acceleration due to gravity.

The ball's initial vertical velocity is (76 m/s) sin(25º) ≈ 32.12 m/s.

Its initial horizontal velocity is (76 m/s) cos(25º) ≈ 68.88 m/s.

The ball stays in the air for as long as y > 0. Solve y = 0 for t :

(76 m/s) sin(25º) t - 1/2 g t² = 0

t ((76 m/s) sin(25º) - 1/2 g t ) = 0

t = 0 or (76 m/s) sin(25º) - 1/2 g t = 0

Ignore the first solution.

(76 m/s) sin(25º) - 1/2 g t = 0

(76 m/s) sin(25º) = (4.90 m/s²) t

t = (76 m/s) sin(25º) / (4.90 m/s²)

t ≈ 6.55 s

Recall that

v² - u² = 2 a ∆y

where u and v denote initial and final velocities, a is acceleration, and ∆y is displacement. At maximum height, the ball has zero vertical velocity, and taking the ball's starting position on the ground to be the origin, ∆y refers to the maximum height. So we have

0² - ((76 m/s) sin(25º))² = 2 (-g) ∆y

∆y = ((76 m/s) sin(25º))² / (2g)

∆y ≈ 52.6 m

5 0

3 years ago

Rafaela is a physical education teacher and has2525 girls and 3535 boys in herclass.She wants to divide the class into teams of

Paha777 [63]

-- The greatest common factor of 2525 and 3535 is 5.

-- So the greatest possible number of teams is 5.

-- Each of the five teams will have 505 girls and 707 boys.

-- Rafaela is a superwoman ! She's handling more kids in that class than there were in my whole high school !

She has 6,060 students in her class, so I'm not surprised that she wants to divide the class up into smaller groups.

But come on ! She's going to form 5 teams, and she thinks that her job will be easier that way, because each team will have 'only' 1,212 students on it !

And these are all in one class ! If Rafaela is a physical education teacher, then SURELY she's teaching more than one class !

Or maybe not. I'll betcha whenever Rafaela is teaching her physical education class, all the other teachers are taking it easy, because Rafaela is responsible for every student in the school that hour.

And possibly several OTHER schools in town too.

7 0

3 years ago

Capacitor C1 is initially charged to V1 and capacitor C2 is initially charged to V2. The capacitors are then connected to each o

disa [49]

Answer:

ΔV = 20.1 V

Explanation:

As the positive plates are connected to each other, the capacitors are connected in parallel, so the total system load is the sum of the charges on each capacitor.

Q = Q₁ + Q₂

The charge on each capacitor is

Q₁ = C₁ ΔV₁

Q₁ = 24 10⁻⁶ 25

Q₁ = 6.00 10⁻⁴ C

Q₂ = C₂ ΔV₂

Q₂ = 13 10⁻⁶ 11

Q₂ = 1.43 10⁻⁴ C

The total set charge is

Q = (6 + 1.43) 10⁻⁴

Q = 7.43 10⁻⁴ C

The equivalent capacitance is

C_eq = C₁ + C₂

C_eq = (24 + 13) 10⁻⁶

C_eq = 37 10⁻⁶ F

Let's use the relationship to find the voltage

Q = C_eq ΔV

ΔV = Q / C_eq

ΔV = 7.43 10⁻⁴ / 37 10⁻⁶

ΔV = 2.008 10¹

ΔV = 20.1 V

This voltage is constant in the combination so it is also the voltage in capacitor C1

3 0

4 years ago