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Brut [27]
3 years ago
5

When a glacier moves, rocks and sediments in the bottom of the glacier scrape against the ground. This creates grooves known as

Physics
2 answers:
Leya [2.2K]3 years ago
8 0

Answer: D. glacial striations

Explanation:

Glaciers striations are the features formed over the bedrock due to glacier erosion. This occurs due to glacier abrasion that happens during glacier erosion or retreating glacier. This results in the formation of striations into multiple straight parallel lines and scrape marks over the bedrock or ground. These striations appear as grooves.

nikdorinn [45]3 years ago
5 0

Answer:

D. Glacial striations

Explanation:

Glacial striations are marks and grooves carved on a rock surface as the materials carried by it abraded the surfaces of the earth.

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A photoelectric effect experiment finds a stopping potential of 1.93 V when light of wavelength 200 nm is used to illuminate the
GenaCL600 [577]

a) Zinc (work function: 4.3 eV)

The equation for the photoelectric effect is:

E=\phi + K (1)

where

E=\frac{hc}{\lambda} is the energy of the incident photon, with

h = Planck constant

c = speed of light

\lambda = wavelength

\phi = work function of the metal

K = maximum kinetic energy of the photoelectrons emitted

The stopping potential (V) is the potential needed to stop the photoelectrons with maximum kinetic energy: so, the corresponding electric potential energy must be equal to the maximum kinetic energy,

eV=K

So we can rewrite (1) as

E=\phi + eV

where we have:

\lambda=200 nm = 2\cdot 10^{-7} m

V = 1.93 V

e is the electron charge

First of all, let's find the energy of the incident photon:

E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2\cdot 10^{-7}m}=9.95\cdot 10^{-19} J

Converting into electronvolts,

E=\frac{9.95\cdot 10^{-19}J}{1.6\cdot 10^{-19} J/eV}=6.22 eV

And now we can solve eq.(1) to find the work function of the metal:

\phi = E-eV=6.22 eV-1.93 eV=4.29 eV

so, the metal is most likely zinc, which has a work function of 4.3 eV.

b) The stopping potential is still 1.93 V

Explanation:

The intensity of the incident light is proportional to the number of photons hitting the surface of the metal. However, the energy of the photons depends only on their frequency, so it does not depend on the intensity of the light. This means that the term E in eq.(1) does not change.

Moreover, the work function of the metal is also constant, since it depends only on the properties of the material: so \phi is also constant in the equation. As a result, the term (eV) must also be constant, and therefore V, the stopping potential, is constant as well.

6 0
3 years ago
How does temperature influence the appearance of a star? Give an example in your response.
loris [4]

The cooler the temp of the star the star would appear to glisten a red. if the star is warmer the star would be a light blue or blue. An example would be the tiny red dwarf stars. they only have 7% of the suns heat so they appear red.

5 0
3 years ago
What do velocity and acceleration have in common?
Allushta [10]
Acceleration is the change in velocity
8 0
3 years ago
Read 2 more answers
Swinging a golf club toward a golf<br> ball and hitting it off the tee.
Vlad1618 [11]

Answer:

sucks cocka-doodle-doooooooo

Explanation:

he likes it jsjsjsjsjsjsjjjsnsns

7 0
3 years ago
Read 2 more answers
We wrap a light, nonstretching cable around a 8.00 kg solid cylinder with diameter of 30.0 cm. The cylinder rotates with negligi
antoniya [11.8K]

Answer:

h = 16.67m

Explanation:

If the kinetic energy of the cylinder is 510J:

Kc=510=1/2*Ic*\omega c^2

\omega c=\sqrt{510*2/Ic}

Where the inertia is given by:

Ic=1/2*m_c*R_c^2=1/2*(8)*(0.15)^2=0.0225kg.m^2

Replacing this value:

\omega c=106.46rad/s

Speed of the block will therefore be:

V_b=\omega_c*R_c=106.46*0.15=15.969m/s

By conservation of energy:

Eo = Ef

Eo = 0

Ef = 510+1/2*m_b*V_b^2-m_b*g*h

So,

0 = 510+1/2*m_b*V_b^2-m_b*g*h

Solving for h we get:

h=16.67m

3 0
3 years ago
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