Answer:
Angle of incline is 20.2978°
Explanation:
Given that;
Gravitational acceleration on a planet a = 3.4 m/s²
Gravitational acceleration on Earth g = 9.8 m/s²
Angle of incline = ∅
Mass of the stone = m
Force on the stone along the incline will be;
F = mgSin∅
F = ma
The stone has the same acceleration as that of the gravitational acceleration on the planet.
so
ma = mgSin∅
a = gSin∅
Sin∅ = a / g
we substitute
Sin∅ = (3.4 m/s²) / (9.8 m/s²)
Sin∅ = 0.3469
∅ = Sin⁻¹( 0.3469 )
∅ = 20.2978°
Therefore, Angle of incline is 20.2978°
+ 1.58 e -15
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The new period is D) √2 T

<h3>Further explanation</h3>
Let's recall Elastic Potential Energy and Period of Simple Pendulum formula as follows:

where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>


where:
<em>T = period of simple pendulum ( s )</em>
<em>L = length of pendulum ( m )</em>
<em>g = gravitational acceleration ( m/s² )</em>
Let us now tackle the problem!

<u>Given:</u>
initial length of pendulum = L₁ = L
initial mass = M₁ = M
final length of pendulum = L₂ = 2L
final mass = M₂ = 2M
initial period = T₁ = T
<u>Asked:</u>
final period = T₂ = ?
<u>Solution:</u>






<h3>Learn more</h3>

<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity