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creativ13 [48]
3 years ago
13

Una rapidez de 7 mm/us es igual a: A) 7000m/s B) 70 m/s C) 7 m/s D) 0.07 m/s

Physics
1 answer:
Ivan3 years ago
3 0

For this conversion you should know that 1 meter has 1000 millimeters and that 1s equals 1000000 micro seconds, then:


7mm/us * 1m/1000mm * 1000000us/1s = 7000 m/s

The mm are canceled just like the micro seconds and the result remains in m / s .

Therefore option A is correct

A) 7000m / s




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The net force of the object is equal to the force applied minus the force of friction. 
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                           12 kg x 0.2 m/s² = 15 N - Ff
The value of Ff is 12.6 N. This force is equal to the product of the normal force which is equal to the weight in horizontal surface and the coefficient of friction.
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3 years ago
Jupiter has a mass of 1,898,000,000,000,000,000,000,000,000 kg. How would
Natasha2012 [34]

Answer:

B.1.898^27 kg

Explanation:

4 0
3 years ago
If a 7 kg bowling ball is lifted 2 m into the air and dropped, what speed will it strike the ground? (
Naily [24]

Answer:

6.32m/s

Explanation:

note:Now these calculations are based in the fact that acc. due to gravity is 10m/s²

okay so I'm thinking you think the speed of a body depends on the mass of the body also,umh... well it doesn't at all!

when two bodies of different masses fall from the same height,they fall at the same time( this is just to say)

now enough of the talking let solve....

so the ball was dropped .ie from rest to the ground through a distance of 2m,

the formula for calculating the distance if a body moving in a straight line is given by:

S=ut + ½at² where u is initial velocity, a is acceleration ( of the body or due to gravity, but since its falling freely under the influence of gravity its " we use the acceleration due to gravity ,which is 10m/s²) and t is the time taken to cover the distance.

from our question the ball was dropped from rest thus its u is 0 therefore we use this equation to find the time it took to touch ground (S=½at²)

solving ....

we get t to be 0.632s

to find the speed we substitute t in the equation below:

V=u+at ,but since u=0

V=at =10•0.632=6.32m/s

therefore the speed the body uses to strike the ground is 6.32m/s

4 0
2 years ago
You are performing a knee extension exercise. You hold a 20kg weight at full knee extension. The weight is 0.4m from your knee j
dmitriy555 [2]

Answer:

The moment is -78.4 N-m (clockwise).

Explanation:

Given:

Mass of the object (m) = 20 kg

Distance of the object from the knee joint (d) = 0.4 m

Weight of leg is not considered.

Acceleration due to gravity (g) = 9.8 m/s²

Now, weight of the object is equal to the product of its mass and acceleration due to gravity. So,

Weight = Mass × Acceleration due to gravity

            = mg=20\times 9.8 =196\ N

We know that, moment of a force about a point is defined as the product of force applied and the perpendicular distance between the point and the line of application of force.

Moment of the given weight about the knee joint is given as:

Moment about knee joint = Weight × Distance from knee joint to weight

Moment about knee joint = 196 × 0.4 = 78.4 Nm

Now, from the diagram below, we can observe that, the weight acts vertically down and thus the sense of rotation about the knee joint at point O is clockwise. So, moment is negative.

Therefore, the moment is -78.4 N-m (clockwise).

7 0
3 years ago
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Makovka662 [10]

Answer:

20m/s

Explanation:

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3 0
2 years ago
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