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valina [46]
3 years ago
14

How do I solve qudratic equations with factions, like this one:

0" id="TexFormula1" title=" \frac{5}{3} " alt=" \frac{5}{3} " align="absmiddle" class="latex-formula">x²-5= 0
Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0
There are several approaches.

(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.

Thus, the quadratic formula would be appropriate here:

         -0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x  = -------------------------------------------------------
                                 2(5/3)
         plus or minus sqrt(100/3)
    = ------------------------------------
                         10/3
            3      10
     = ------* ----------- = sqrt(3)    (answer)
          10     sqrt(3)
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3 years ago
The cost to rent a raft is $7 per person. A raft can hold up to 6 people. There is a $3 launch fee per raft. What is the total c
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8 0
3 years ago
A sector with an area of 26pie cm^2 has a radius of 6 cm. What is the central angle measure of the sector in radians?
Zolol [24]

Answer:

The central angle measure of the sector in radians is \theta=\frac{13}{9}.

Step-by-step explanation:

A sector of a circle is the portion of a circle enclosed by two radii and an arc. It resembles a "pizza" slice.

The area of a sector when the central angle is in radians is given by

                                                    A=(\frac{\theta}{2})\cdot r^2

where

r = radius

θ = central angle in radians

We know that the area of the sector is 26 \:cm^2 and the radius is 6 cm. Applying the above formula and solving for the central angle (\theta) we get that

                                                   26=(\frac{\theta}{2})\cdot (6)^2\\\\\left(\frac{\theta}{2}\right)\left(6\right)^2=26\\\\\frac{\frac{\theta}{2}\cdot \:6^2}{36}=\frac{26}{36}\\\\\frac{\theta}{2}=\frac{13}{18}\\\\\theta=\frac{13}{9}

3 0
3 years ago
(3, -5)(0, 4)<br> Write the equation of a line using the point slope formula
Serga [27]

Answer:

y = - 3x + 4

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (3, - 5) and (x₂, y₂ ) = (0, 4)

m = \frac{4-(-5)}{0-3} = \frac{4+5}{-3} = \frac{9}{-3} = - 3

The line crosses the y- axis at (0, 4) ⇒ c = 4

y = - 3x + 4 ← equation of line

7 0
3 years ago
A function is shown on the graph what is the domain of the function?
Ronch [10]

Answer:

you need to add the graph

6 0
3 years ago
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