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valina [46]
3 years ago
14

How do I solve qudratic equations with factions, like this one:

0" id="TexFormula1" title=" \frac{5}{3} " alt=" \frac{5}{3} " align="absmiddle" class="latex-formula">x²-5= 0
Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0
There are several approaches.

(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.

Thus, the quadratic formula would be appropriate here:

         -0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x  = -------------------------------------------------------
                                 2(5/3)
         plus or minus sqrt(100/3)
    = ------------------------------------
                         10/3
            3      10
     = ------* ----------- = sqrt(3)    (answer)
          10     sqrt(3)
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<h2>Question:</h2>

Find k if (x+1) is a factor of 2x³ + kx² + 1

<h2>Answer:</h2>

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<h2>Step-by-step explanation:</h2>

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<em>This is because;</em>

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<em><u>From the question</u></em>

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

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