A car traveled for 6 hours on one highway and for 2 hours on a second highway. If the total distance traveled was 488 miles, and
the car traveled 12 miles per hour faster on the second highway, at what average speed was the car traveling on the second highway?
1 answer:
6V + 2(V+12) = 488
8V = 464
V = 58 mph for 6 hours
V+12=70 mph for 2 hours.
check: 58*6 = 348
70*2 = 140
348 +140 =488
the car was traveling at 70 mph on the 2nd highway
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