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IgorLugansk [536]
4 years ago
11

Help ineed to find this.

Mathematics
2 answers:
omeli [17]4 years ago
5 0
She saved up a total of $82.60, and had to spend a total of $60.90, so she would have $21.70 left and need to save up another $180.40, hope this helps
myrzilka [38]4 years ago
3 0
Take all Sara's money that she saved and add it together. Then minus 20.20 and 40.70 from Sara's saved money. With the rest of the Sara's money you have to subtract it from 130.10.
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CAN ANYONE HELP ME ANSWER THIS PLEASE​
HACTEHA [7]

Answer: 14/45

Step-by-step explanation: The probability that they first event will occur is 2/10. The probability that the second event will occur is 1/9. If you multiply those like it says in the hint you will get 14/45. (I think this is right)

5 0
3 years ago
What is 5/8x+4=3/8x+12
Semmy [17]

Answer:

x = 32

(The answer should be 32 if we are solving for x)

6 0
3 years ago
Which of the following angles is NOT congruent to 6?<br> 3<br> 2<br> 7<br> 1
TiliK225 [7]

Answer:

1

Step-by-step explanation:

We can see that 7 is equal to 6, as opposite angles are the same.

We can also see that 2 is also 6, as corresponding angles are equivalent.

Therefore, 3 is also congruent to 6, as it is equal to 2.

Hope that this helps!

8 0
3 years ago
Multiply the quotient " 16 and 2 by 2" write in two different ways
zzz [600]
16/2 times 2 =16, 2/2 times 16 = 16
4 0
3 years ago
The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and me
Dovator [93]

Answer:

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The problem states that:

The number of phone calls that Actuary Ben receives each day has a Poisson distribution with mean 0.1 during each weekday and mean 0.2 each day during the weekend.

To find the mean during the time interval, we have to find the weighed mean of calls he receives per day.

There are 5 weekdays, with a mean of 0.1 calls per day.

The weekend is 2 days long, with a mean of 0.2 calls per day.

So:

\mu = \frac{5(0.1) + 2(0.2)}{7} = 0.1286

If today is Monday, what is the probability that Ben receives a total of 2 phone calls in a week?

This is P(X = 2). So:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 2) = \frac{e^{-0.1286}*0.1286^{2}}{(2)!} = 0.0073

There is a 0.73% probability that Ben receives a total of 2 phone calls in a week.

3 0
3 years ago
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