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3 years ago

9 hundred thousands = how many ten thousands

Mathematics

2 answers:

WITCHER [35]3 years ago

7 0

Answer:

90 is the answer

Step-by-step explanation:

timofeeve [1]3 years ago

6 0

Answer:

90 is the answer:)

Step-by-step explanation:

I hope it helps you. Have a marvellous day!

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Find the area I will make you Brainliest (show working) the bottom number is 8 cm where it says liveworksheets

ki77a [65]

Answer:

228cm^2

Step-by-step explanation:

Multiply 18cm by 10cm:

18 x 10 = 180cm^2

So we have the area of the biggest/top part: 180cm^2

For the bottom part:

You've said the length of the bottom side is 8cm.

We know the length of the biggest side: 24cm. And we know the length of the opposite side: 18cm. So, to find the length of the missing side, it's simple subtraction:

24cm - 18cm = 6cm

So now we have lengths for 2 sides: 8cm and 6cm.

Multiply these to give the area:

8cm * 6cm = 48cm^2

Add these areas of both shapes together to give total area:

180cm^2 + 48cm^2 = 228cm^2

8 0

2 years ago

Simplify this (2x)^{3}

Margaret [11]

Answer:

8x^3

Step-by-step explanation:

(2x)3

=(2x)3

=2x*2x*2x

=8x^3

7 0

2 years ago

B) 75: 125 help me solve it

mash [69]

75:125

divide both sides by 25

75/25= 3

125/25= 5

Answer: 3:5

4 0

3 years ago

Can you identify the value of each digit ?

Licemer1 [7]

Answer:WHAT VALUE AND WHAT DIGIT

Step-by-step explanation:

4 0

2 years ago

B. Determine the values of a and b so that f is continuous.<br><br> Please help!

wlad13 [49]

Answer:

following are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attached file.

$\lim_{x\to 2}+f(x) = \lim_{x\to 2}+ (ax^2-bx+3) = 4a-2b+3\\\\ \to 4a-2b+3 = 4\\\\ \therefore \ \ 4a-2b = 1\\\\$

The one-sided limits of F(x) at x = 3 must be equivalent for f(x) to be continuous at x = 3.

$\to \lim_{x\to 3}- f(x) = \lim_{x\to 3}- (ax^2-bx+3) = 9a-3b+3\\\\ \to \lim_{x\to 3}+ f(x) = \lim_{x\to 3}+ (2x-a+b) = 6-a+b\\\\$

So,

$\to 9a-3b+3 = 6-a+b\\\\\therefore\\ \to 10a -4b = 3$

$\to 4a - 2b = 1......(a)\\\to 10a - 4b = 3.......(b)\\$

In equation a multiply the by -2 and then add in the equation b:

$\to -8a + 4b = -2\\\to 10a - 4b = 3\\ \to 2a = 1\\\\ \to a = \frac{1}{2}\\\\ \to \ 4(\frac{1}{2}) - 2b = 1\\\\ \to 2 - 2b = 1\\\\ \to -2b = -1\\\\ \to b = \frac{1}{2}$

So, the value of $a \ and \ b= \frac{1}{2}$

4 0

2 years ago