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MrMuchimi
3 years ago
7

a boat sails along the shore. to an observer, the boat appears to move at a speed of 3m/s, and a man on the boat walking foward

appears to have a speed of 4.2 m/s how long does it take the man to move 8 m relative to the boat?
Physics
1 answer:
lina2011 [118]3 years ago
6 0
It is 6.7s. you need to slove the promble
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The Surface Pressure at Leh, Ladakh is 800 mb. Now, assuming that Leh is at an altitude of 3500 m and every 100 m increase in he
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We have that the sea level pressure for Leh area is 1150mb mathematically given as

Ps= 1150 mb

<h3> Sea level pressure</h3>

Question Parameters:

Ladakh is 800 mb.

<u>assuming </u>that Leh is at an altitude of 3500 m and every 100 m

increase in height with respect to sea level corresponds to 10 mb pressure,

Generally, for 3500m the pressure change will be 350 mb.

Therefore,  here for the sea level <em>pressure</em> we need to add,

Ps=800+350

Ps= 1150 mb

For more information on Pressure visit

brainly.com/question/25688500

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2 years ago
A particle released during the fission of uranium-235 is a(n) ________
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<span>A particle released during the fission of uranium-235 is a "Neutron"</span>
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3 years ago
All moving objects don’t have momentum<br> A. True<br> B. False
mestny [16]

Answer:

No

Explanation:

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4 0
3 years ago
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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista
lions [1.4K]
The answer is 60 mph.

The speed (v) is distance (d) per time (t): v = d/t

Car A:
v1 = ?
t1 = 2 h
d1 = ?
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v1 = d1/t1
d1 = v1 * t1

Car B:
v2 = ?
t2 = 1.5 h
d2 = ?
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v2 = d2/t2
d2 = v2 * t2

<span>Two cars traveled equal distances:
d1 = d2
</span>v1 * t1 = v2 * t2

<span>Car B traveled 15 mph faster than Car A:
v2 = v1 + 15


</span>v1 * t1 = v2 * t2
v2 = v1 + 15
________
v1 * 2 = (v1 + 15) * 1.5
2v1 = 1.5v1 + 22.5
2v1 - 1.5v1 = 22.5
0.5v1 = 22.5
v1 = 22.5/0.5
v1 = 45 mph


v2 = v1 + 15
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8 0
3 years ago
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solniwko [45]

Answer:

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3 years ago
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