Answer:
a) F = 1.70 10⁻⁹N, F = 1.47 10⁻⁸ N,
b) * the electronegative repulsion, from the repulsion by quantum effects
Explanation:
a) The atraicione force comes from the electric force given by Coulomb's law,
F =
divalent atoms
In this case q = 2q₀ where qo is the charge of the electron -1,6 10⁻¹⁹ C and the separation is given
F = k q² / r²
F =
F = 1.70 10⁻⁹N
monovalent atoms
in this case the load is q = q₀
F = 2 \ 10^9 \ \frac{ (1.6 \ 10^{-19} )^2}{ (0.125 10^{-9} )^2 }
F = 1.47 10⁻⁸ N
b) repulsive forces come from various sources
* the electronegative repulsion of positive nuclei
* the electrostatic repulsion of the electrons when it comes to bringing the electron clouds closer together
* from the repulsion of electron clouds, by quantum effects
Given,
The force applied to lift the tree, F=150 N
The work done in lifting the tree, W=250 J
The work done in lifting the tree is the product of the force applied and the height through which the tree was lifted.
Thus,
Where d is the height through which the tree was lifted.
On substituting the known values,
Thus the tree was lifted through a height of 1.67 m
Answer:
705.6 m
Explanation:
time, t = 12 sends
initial velocity, u = 0
Acceleration due to gravity, g = - 9.8 m/s^2
As the object is falling freely so the initial velocity is zero.
Let the distance traveled by the body is h in time t = 12 s.
Use second equation of motion
Ad the distance is downwards so take it as negative
So,
h = 705.6 m
Thus, the distance traveled in 12 second is 705.6 m
Answer:
The magnitude of the force is
Explanation:
Given that,
Electric field intensity
Suppose, The electron when positioned at this location
We need to calculate the magnitude of the force
Using formula of electric field
Where, E = electric field
q = charge of electron
Put the value into the formula
Hence, The magnitude of the force is