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pav-90 [236]
3 years ago
9

1. Solve: When you mix two substances, the heat gained by one substance is equal to the heat

Physics
1 answer:
hram777 [196]3 years ago
5 0

Answer:

So heat required to raise the temperature of water is given as Q = 33472 J

Explanation:

As we know that the temperature of water is increased by 2 Degree C

So here we have heat gain by the water is given by the equation

Q = m s\Delta T

Now we know that

m = 1000 g

s = 4.184 J/g C

Now plug in all data in above equation

Q = 1000(4.184)(2)

Q = 33472 J

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As a projectile falls, what happens to the components of velocity?
netineya [11]

Answer:

Option (c).

Explanation:

An object when when projected at an angle, will have some horizontal velocity and vertical velocity such that,

v_x=v\cos\theta\ \text{and}\ v_y=v\sin\theta

\theta is the angle of projection

The horizontal component of the projectile remains the same because there is no horizontal motion. Vertical component changes at every point.

As a projectile falls, vertical velocity increases in magnitude, horizontal velocity stays the same .

7 0
3 years ago
How is sunlight different from light produced by a light bulb or by a fluorescent light bulb
Leona [35]
Sunlight emits more energy than artificial light. Sunlight is better and healthier than most artificial lights and helps plants to grow more.
4 0
3 years ago
A turtle ambles leisurely, as turtles tend to do, when it moves from a location with position vector 1,=1.91 m and 1,=−2.73 m in
Elena-2011 [213]

Answer:

Components: 0.0057, -0.0068. Magnitude: 0.0089 m/s

Explanation:

The displacement in the x-direction is:

d_x = 3.65-1.91=1.74 m

While the displacement in the y-direction is:

d_y = -4.79 -(-2.73)=-2.06 m

The time taken is t = 304 s.

So the components of the average velocity are:

v_x = \frac{d_x}{t}=\frac{1.74}{304}=0.0057 m/s

v_y = \frac{d_y}{t}=\frac{-2.06}{304}=-0.0068 m/s

And the magnitude of the average velocity is

v=\sqrt{v_x^2+v_y^2}=\sqrt{(0.0057)^2+(-0.0068)^2}=0.0089 m/s

8 0
3 years ago
Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls th
UNO [17]

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

s=\frac{1}{2}gt^2

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance s_A during a time t, so the distance covered by object A is

s_A=\frac{1}{2}gt^2

- Object B falls through a distance s_B during a time 2t, so the distance covered by object B is

s_B=\frac{1}{2}g(2t)^2 = 4(\frac{1}{2}gt^2)=4s_A

So, the distance covered by object B is 4 times the distance covered by object A.

5 0
2 years ago
What force is required to move an object 8 m using 24 j of work?
Anna35 [415]

Answer:

3N

Explanation:

Workdone = F x d

F = force

d = distance 8m

Workdone = 24J

24 = F x 8

Divide both sides by 8

24/8 = F x 8/8

3 = F

F = 3N

7 0
2 years ago
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