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3 years ago

5

The electric field intensity at a particular location surrounding a Van de Graaff generator is 4.5x103 N/C. Determine the magnit

ude of the force that this field would exert upon ...

2 answers:

puteri [66]3 years ago

8 0

Answer:

Explanation:

Electric field, E = 4.5 x 10^3 N/C

charge on electron, e = 1.6 x 10^-19 C

The relation between the force and the electric field is given by

F = q E

F = 1.6 x 10^-19 x 4.5 x 10^3

F = 7.2 x 10^-16 N

Oksanka [162]3 years ago

3 0

Answer:

The magnitude of the force is $7.2\times10^{-16}\ N$

Explanation:

Given that,

Electric field intensity $E= 4.5\times10^3$

Suppose, The electron when positioned at this location

We need to calculate the magnitude of the force

Using formula of electric field

$E = \dfrac{F}{q}$

$F = Eq$

Where, E = electric field

q = charge of electron

Put the value into the formula

$F=4.5\times10^3\times1.6\times10^{-19}$

$F=7.2\times10^{-16}\ N$

Hence, The magnitude of the force is $7.2\times10^{-16}\ N$

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Which process causes the transfer of energy by air currents within the Earth's atmosphere?

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Answer:

Conduction, radiation and convection all play a role in moving heat between Earth's surface and the atmosphere. Since air is a poor conductor, most energy transfer by conduction occurs right near Earth's surface

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3 years ago

What does activation energy has to do with a chemical reaction.

asambeis [7]

Explanation:

Activation energy and reaction rate

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3 years ago

A roller coaster is at the top of a 102 m hill and a mass of 120 kg. The coaster (at this

dybincka [34]

Height=h=102m
Mass=m=120g
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$\\ \sf\longmapsto P.E=mgh$

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7 0

3 years ago

PLEASE ANSWER AS QUICK AS POSSIBLE!!!!!

horsena [70]

During the operation of fan we know that it is working on the electricity

So here when we connect the fan with electricity it uses the electrical energy and convert that energy into mechanical energy of fan

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So here correct answer must be

B.

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4 years ago

A small block of mass M = 0.10 kg is released from rest at point 1 at a height H = 1.8 m above the bottom of a track, as shown i

Ede4ka [16]

Answer:

D

Explanation:

A) is not correct, because the gravitation potential energy will depend on the height the block is located at. It will be calculated with the formula:

U=mgh.

If we take the ground as a zero height reference, then on point 2 the potential energy will be:

$U_{2} = 0.10kg(9.81 m/s^{2})(0.6m)$

$U_{2}=0.59 J$

While on point 3, the potential energy will be greater.

$U_{3}=0.10kg(9.81 m/s^{2})(1.2m)$

$U_{3}=1.18 J$

B) is not the right answer because the kinetic energy will vary with the height the block is located at in the fact that the energy is conserved (this is if we don't take friction into account or air resistance) so in this case:

$U_{2}+K_{2}= U_{3}+K_{3}$

We already know the potential energy at point 2. We can calculate the kinetic energy at point 3 like this:

$K_{3} =\frac{1}{2}mv_{3}^{2}$

$K_{3} =\frac{1}{2}(0.10kg)(2.5 m/s)^{2}$

$K_{3} =0.31 J$

So the kinetic energy at point 2 is given by the equation:

$K_{2} =U_{3}-U_{2}+K_{3}$

so:

$K_{2} = (1.18J)-(0.59J)+0.31J$

$K_{2} =0.9J$

As you may see the kinetic energy at point 2 is greater than the kinetic energy at point 3.

C) Is not correct because according to the first law of thermodinamics, energy is not lost, only transformed. So, since we are not taking into account friction or any other kind of loss, then we can say that the amount of mechanical energy at point 1 is exactly the same as the mechanical energy at point 3.

D) Because of what we talked about on part C, this will be the true situation, because the mechanical energy of the block will be the same no matter theh point you measure it at.

7 0

3 years ago