The minimum coefficient of static friction between the pavement and the tires is 0.69.
The given parameters;
- <em>radius of the curve, r = 90 m</em>
- <em>angle of inclination, θ = 10.8⁰</em>
- <em>speed of the car, v = 75 km/h = 20.83 m/s</em>
- <em>mass of the car, m = 1100 kg</em>
The normal force on the car is calculated as follows;

The frictional force between the car and the road is calculated as;

The net force on the car is calculated as follows;


Thus, the minimum coefficient of static friction between the pavement and the tires is 0.69.
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Answer:
ΔΦ = -3.39*10^-6
Explanation:
Given:-
- The given magnetic field strength B = 0.50 gauss
- The angle between earth magnetic field and garage floor ∅ = 20 °
- The loop is rotated by 90 degree.
- The radius of the coil r = 19 cm
Find:
calculate the change in the magnetic flux δφb, in wb, through one of the loops of the coil during the rotation.
Solution:
- The change on flux ΔΦ occurs due to change in angle θ of earth's magnetic field B and the normal to circular coil.
- The strength of magnetic field B and the are of the loop A remains constant. So we have:
Φ = B*A*cos(θ)
ΔΦ = B*A*( cos(θ_1) - cos(θ_2) )
- The initial angle θ_1 between the normal to the coil and B was:
θ_1 = 90° - ∅
θ_1 = 90° - 20° = 70°
The angle θ_2 after rotation between the normal to the coil and B was:
θ_2 = ∅
θ_2 = 20°
- Hence, the change in flux can be calculated:
ΔΦ = 0.5*10^-4*π*0.19*( cos(70) - cos(20) )
ΔΦ = -3.39*10^-6
Answer:
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Explanation:
The waves from highest to lowest are :
* Gamma
* X- Rays
* UV
* Visible
* Infrared
* Microwaves
* Radio-waves
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Answer:
-you have to make yourse;f as light as possible so toss your bag, jacket, and shoes.
-Try to take a few steps backwards.
-Keep your arms up and out of the quicksand.
-Try to reach for a branch or person's hand to pull yourself out.
-Take deep breaths.
-Move slowly and deliberately.