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zvonat [6]
3 years ago
5

The electric field intensity at a particular location surrounding a Van de Graaff generator is 4.5x103 N/C. Determine the magnit

ude of the force that this field would exert upon ...
Physics
2 answers:
puteri [66]3 years ago
8 0

Answer:

Explanation:

Electric field, E = 4.5 x 10^3 N/C

charge on electron, e = 1.6 x 10^-19 C

The relation between the force and the electric field is given by

F = q E

F = 1.6 x 10^-19 x 4.5 x 10^3

F = 7.2 x 10^-16 N

Oksanka [162]3 years ago
3 0

Answer:

The magnitude of the force is 7.2\times10^{-16}\ N

Explanation:

Given that,

Electric field intensity E= 4.5\times10^3

Suppose, The electron when positioned at this location

We need to calculate the magnitude of the force

Using formula of electric field

E = \dfrac{F}{q}

F = Eq

Where, E = electric field

q = charge of electron

Put the value into the formula

F=4.5\times10^3\times1.6\times10^{-19}

F=7.2\times10^{-16}\ N

Hence, The magnitude of the force is 7.2\times10^{-16}\ N

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