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zvonat [6]
3 years ago
5

The electric field intensity at a particular location surrounding a Van de Graaff generator is 4.5x103 N/C. Determine the magnit

ude of the force that this field would exert upon ...
Physics
2 answers:
puteri [66]3 years ago
8 0

Answer:

Explanation:

Electric field, E = 4.5 x 10^3 N/C

charge on electron, e = 1.6 x 10^-19 C

The relation between the force and the electric field is given by

F = q E

F = 1.6 x 10^-19 x 4.5 x 10^3

F = 7.2 x 10^-16 N

Oksanka [162]3 years ago
3 0

Answer:

The magnitude of the force is 7.2\times10^{-16}\ N

Explanation:

Given that,

Electric field intensity E= 4.5\times10^3

Suppose, The electron when positioned at this location

We need to calculate the magnitude of the force

Using formula of electric field

E = \dfrac{F}{q}

F = Eq

Where, E = electric field

q = charge of electron

Put the value into the formula

F=4.5\times10^3\times1.6\times10^{-19}

F=7.2\times10^{-16}\ N

Hence, The magnitude of the force is 7.2\times10^{-16}\ N

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The temperature at a point (x, y) on a flat metal plate is given by T(x, y) = 54/(7 + x2 + y2), where T is measured in °C and x,
ANTONII [103]

Answer:

dt/dx = -0.373702

dt/dy =  -1.121107

Explanation:

Given data

T(x, y) = 54/(7 + x² + y²)

to find out

rate of change of temperature with respect to distance

solution

we know function

T(x, y) = 54 /( 7 + x² + y²)

so derivative it x and y direction i.e

dt/dx = -54× 2x / (7 +x² + y²)²    .........................1

dt/dy = -54× 2y / (7 + x² + y²)²      .........................2

now put the value point (1,3) as x = 1 and y = 3 in equation 1 and 2

dt/dx = -54× 2(1) / (7 +(1)² + (3)²)²  

dt/dx = -0.373702

and

dt/dy =  -54× 2(3) / (7 + (1)² + (3)²)²

dt/dy =  -1.121107

7 0
3 years ago
A car moving west slows down from a velocity of 50 m/s to 20 m/s in 15 seconds. What is its acceleration?
velikii [3]
Vf = Vo + at

Vf = 20 m/s
Vo = 50 m/s
a = ? 
t = 15

Therefore

20 = 50 + 15a

20 - 50 = 15a

-30 = 15a

a = -30 / 15

a = -2 m/s²
6 0
3 years ago
Accelerating charges radiate electromagnetic waves. Calculate the wavelength of radiation produced by a proton of mass mp moving
Iteru [2.4K]

Explanation:

Let m_p is the mass of proton. It is moving in a circular path perpendicular to a magnetic field of magnitude B.

The magnetic force is balanced by the centripetal force acting on the proton as :

\dfrac{mv^2}{r}=qvB

r is the radius of path,

r=\dfrac{mv}{qB}

Time period is given by :

T=\dfrac{2\pi r}{v}

T=\dfrac{2\pi m_p}{qB}

Frequency of proton is given by :

f=\dfrac{1}{T}=\dfrac{qB}{2\pi m_p}

The wavelength of radiation is given by :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{2\pi m_pc}{qB}

So, the wavelength of radiation produced by a proton is \dfrac{2\pi m_pc}{qB}. Hence, this is the required solution.

3 0
3 years ago
Q 2 Two mirrors meet at right angles. A ray of light is incident on one at an angle of 30°
serg [7]

a ray of light is incident towards a plane mirror at an angles of 30degrees with the mirror surface. what will be the angles of reflection is 60degree.

3 0
3 years ago
3. A microwave oven draws 12 A of current on a 110 V household circuit. What is its power
steposvetlana [31]

Answer:

W = 1320Watts

Explanation:

W = I*V

W = 12A*110V

W = 1320Watts

7 0
3 years ago
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