The cost of two tables and three chairs is 705$ if the table costs 40$ more than the chair find the cost of one table and two ch
airs
1 answer:
Chair= x
Table= x+40
2(x+40)+3x=705
2x+80+3x=705
5x+80=705
5x=705-80
5x=625
x= 625/5
x=125
1 chair costs $125
1 table costs $165
The cost of 1 table and two chairs-----> 165+125+125= $415
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