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vaieri [72.5K]
3 years ago
8

The cost of two tables and three chairs is 705$ if the table costs 40$ more than the chair find the cost of one table and two ch

airs
Mathematics
1 answer:
zhuklara [117]3 years ago
8 0
Chair= x
Table= x+40

2(x+40)+3x=705
2x+80+3x=705
5x+80=705
5x=705-80
5x=625
x= 625/5
x=125

1 chair costs $125
1 table costs $165

The cost of 1 table and two chairs-----> 165+125+125= $415

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Anastaziya [24]

Answer:

See below

Step-by-step explanation:

58.4/9.6 can be rewritten as 58/10=5.8, so the decimal point will go between the first and second digits. Therefore, 58.4/9.6=6.083

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3 years ago
Solve by using elimination. Express your answer as an ordered pair.
12345 [234]

Answer:

(-2, 5)

Step-by-step explanation:

we subtract 6x+3y=3 by 2x+3y=11 to get 4x=-8.

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3 years ago
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kvv77 [185]

Answer:

a) The 99% confidence interval would be given by (5004.168;12603.832)

b) For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X =9004 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=5629 represent the sample standard deviation

n=20 represent the sample size  

2) Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=20-1=19

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,19)".And we see that t_{\alpha/2}=2.86

Now we have everything in order to replace into formula (1):

9004-2.86\frac{5629}{\sqrt{20}}=5004.168    

9004+2.86\frac{5629}{\sqrt{20}}=12603.832

So on this case the 99% confidence interval would be given by (5004.168;12603.832)    

3) Part b

For this case we can use the lower bound for the confidence interval as estimation, on this case 5004.168. But we need to take in count that this value it's with 99% of confidence and 1% of significance and 1% of probability to commit type Error I

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