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vaieri [72.5K]
3 years ago
8

The cost of two tables and three chairs is 705$ if the table costs 40$ more than the chair find the cost of one table and two ch

airs
Mathematics
1 answer:
zhuklara [117]3 years ago
8 0
Chair= x
Table= x+40

2(x+40)+3x=705
2x+80+3x=705
5x+80=705
5x=705-80
5x=625
x= 625/5
x=125

1 chair costs $125
1 table costs $165

The cost of 1 table and two chairs-----> 165+125+125= $415

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pogonyaev

Answer:

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