It is defined as the difference between the largest and smallest values in the middle 50% of a set of data<span>. To compute an </span>interquartile range<span> using this definition, first remove observations from the lower quartile. Then, remove observations from the upper quartile.</span>
Answer:
Surface area of the cube = 216 square units
Step-by-step explanation:
Let the length of a side of a cube = x unit
Diameter of the sphere inscribed in this cube = length of a side of the cube
Volume of the sphere = 
Where r = radius of the sphere =
units
36π = 
36π = 
36×24 = 4x³
x = ![\sqrt[3]{\frac{36\times 24}{4} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B36%5Ctimes%2024%7D%7B4%7D%20%7D)
x = 6 units
Length of a side of the cube = 6 units
Surface area of the cube = 6×(Side)²
= 6×(6)²
= 216
= 216 square units
Answer:
y=-4x-8
Step-by-step explanation:
use the equation y-y1=m(x-x1) and solve for y
No idea what language you're talking in, sorry but I only understand English? There is no photo here either.
Please Evaluate?
Thank you.