If we draw the contingency table of x (vertical) against y (horiz.), we have a square.
For n=4, we have (legend: < : x<y = : x=y > : x>y
y 1 2 3 4
x
1 = < < <
2 > = < <
3 > > = <
4 > > > =
We see that there are n(n-1)/2 cases of x<y out of n^2.
Therefore,
p(x<y)=n(n-1)/(2n^2)=(n-1)/(2n)
However, if the sample space is continuous, it will be simply p(x<y)=1/2.
7/x = 5/y
Can be changed to:
5x = 7y
So, x = (7/5)y and
y = (5/7)x
Answer:
5
Step-by-step explanation:
2=30 so 30= 1/2 or an hour so 2+2=4 witch makes an gour half of 2 is 1 so it would make 5
We are to find the time at which the height of basketball thrown by Eli and Karl is equal. We have the functions which model the heights of both basketballs. So by equating the functions representing the height of both basketballs we can find the value of x from that equation at which the height is same for both basketballs.

Thus after 1.25 seconds the height of basketballs thrown by Eli and Karl will be at the same height. This can be verified by finding the heights of both at x=1.25
For Eli:

For Karl:

Thus height of both basketball is equal after 1.25 seconds