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Leno4ka [110]
3 years ago
7

PLEASE HELP WILL GIVE BRAINLIEST, THANKS, AND RATE 5 STARS!!!

Mathematics
1 answer:
solmaris [256]3 years ago
3 0

First answer, this is because if you were to substitute the x and y variables which are the height and days the plant grew, then the 1st answer would be the answer

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Find the volume of the sphere. Give the answer in terms of pi and rounded to the nearest cubic foot.
Inessa05 [86]
Hi there!

The formula for the volume of a sphere is V = 4/3(pi)(r^3). Using this formula, we can plug in what we know and solve.

WORK:
V = 4/3(pi)(10^3)
V = 4/3(1000pi)
V = 4000pi/3 or 1333.3 pi
V also = 4188.8

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
3 0
3 years ago
Read 2 more answers
Help in geometry?????
blagie [28]
D because there are 8 outcomes 
3 0
3 years ago
Read 2 more answers
Which function is a quadratic function? u(x) = –x 3x2 – 8 v(x) = 2x2 8x3 9x y(x) = x2 3x5 4 z(x) = 7x2 2x3 – 3.
Komok [63]

The function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

Given functions are:

u(x)=-x+3x^{2} -8

v(x)=2x^{2} +8x^3+9x

y(x)=x^{2} +3x^5+4

z(x) =7x^{2} +2x^3-3

<h3>What is a quadratic function?</h3>

A function of the form f(x)=ax^{2} +bx+c with a\neq 0 is called a quadratic function means the highest exponent of polynomial should be 2.

Let us check one by one.

u(x)=-x+3x^{2} -8

Highest exponent =2

The function is also of form f(x)=ax^{2} +bx+c so u(x) is a quadratic function.

The functions v(x), y(x), and z(x) are having highest exponents as 3,5, and 3 respectively so they are not quadratic functions.

Hence, the function u(x)=-x+3x^{2} -8 is a quadratic function due to the highest exponent being 2.

To get more about quadratic functions visit:

brainly.com/question/1214333

7 0
2 years ago
I thought of a two-digit number. The digits of my number are different. The unit digit of my number is the tens digit raised to
earnstyle [38]

28.

2 to the third power is 8. Therefore, the answer is 28.


Hope this helps!

4 0
3 years ago
Find the smallest positive integer n such that the digit sum of n is divisible by 5, and the digit sum of n +1 is also divisible
alisha [4.7K]

Answer:

139,999

Step-by-step explanation:

If the digit sum of n is divisible by 5, the digit sum of n+1 can't physically be divisble by 5, unless we utilise 9's at the end, this way whenever we take a number in the tens (i.e. 19), the n+1 will be 1 off being divisble, so if we take a number in the hundreds, (109, remember it must have as many 9's at the end as possible) the n+1 will be 2 off being divisble, so continuing this into the thousands being three, tenthousands being 4, the hundred thousands will be 5 off (or also divisble by 5). So if we stick a 1 in the beginning (for the lowest value), and fill the last digits with 9's, we by process of elimination realise that the tenthousands digit must be 3 such that the digit sum is divisible by 5, therefore we get 139,999

6 0
2 years ago
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