12x + 4 ➗ 4 + 20x + 5 ➗ 5
1. PEMDAS (order of operations) solve the division problems
(4 divided by 4 & 5 divided by 5)
12x + 1 + 20x + 1
2. Swap around the order of operations as commutative property states that you can swap the order of an addition problem and get the same answer.
12x + 20x + 1 + 1
3. Add like terms
32x + 2
This is the most simplified answer you could get as you can not add 32x and 2 as they are not like terms.
Answer:
The 4 t h term is f(4) = 143
Step-by-step explanation:
<em>Explanation</em>:-
Given function f(1) = -4
Given 'nth' term is f(n) = -3f(n-1) +5
Put n =2 <em> f(2) = -3 f(2-1) +5</em>
= -3 f(1) +5
= -3 (-4) +5
= 12 +5
f(2) = 17
put n= 3
f(n) = -3f(n-1) +5
<em> f(3) = -3 f(3-1) +5</em>
= -3f(2) +5
= -3(17) +5
= -51+5
f(3) = -46
Put n=4
f(n) = -3f(n-1) +5
<em> f(4) = -3f(4-1) +5</em>
<em> f(4) = -3f(3)+5</em>
f(4) = -3(-46)+5
f(4) = 138 +5
f(4) = 143
<u><em>Final answer</em></u>:-
<em>The 4 t h term is f(4) = 143</em>
9514 1404 393
Answer:
"complete the square" to put in vertex form
Step-by-step explanation:
It may be helpful to consider the square of a binomial:
(x +a)² = x² +2ax +a²
The expression x² +x +1 is in the standard form of the expression on the right above. Comparing the coefficients of x, we see ...
2a = 1
a = 1/2
That means we can write ...
(x +1/2)² = x² +x +1/4
But we need x² +x +1, so we need to add 3/4 to the binomial square in order to make the expressions equal:

_____
Another way to consider this is ...
x² +bx +c
= x² +2(b/2)x +(b/2)² +c -(b/2)² . . . . . . rewrite bx, add and subtract (b/2)²*
= (x +b/2)² +(c -(b/2)²)
for b=1, c=1, this becomes ...
x² +x +1 = (x +1/2)² +(1 -(1/2)²)
= (x +1/2)² +3/4
_____
* This process, "rewrite bx, add and subtract (b/2)²," is called "completing the square"—especially when written as (x-h)² +k, a parabola with vertex (h, k).
Answer:
264647401977373+3637397374+739-739376536372801826464783920182773636373+7373839292901-278282
Answer:
D
Step-by-step explanation:
D) (7 x 1000) + (6 x 100) + (6 x 10) + (4 x 1) + (2 x 1 10 ) + (3 x 1 100 )