Answer:
Midpoint = (3.5, 4.5)
Perpendicular bisector = y = 
x + 
Step-by-step explanation:
[] We can solve this using the midpoint formula:
-> See attached
[] Plug-in our coordinates and solve:
[] Now we will find the slope to solve for the perpendicular bisector.
-> We will use slope-intercept form, see attached
-> The slopes of two perpendicular lines are negative reciprocals of each other, so will be the slope of or perpendicular bisector
-> Now we can solve for the equation by using y – y1 = m ( x – x1), were y1 and x1 are the coordinates of our midpoint
y - 4.5 = (x-3.5)
y - 4.5 = x-
y = x- + 4.5
y = x +
Have a nice day!
I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)
- Heather
I think you forgot to give the options along with the question. I am answering the question based on my research and knowledge. "Some customers who rate their service as high quality return for additional services" is the conclusion that can be drawn from this study. I hope that the answer has actually come to your desired help.
The final price (what it is selling for) is $796.40
The markup is 10% of the original price (the dealer's cost) , meaning that it is 10% more.
We need to find the original price.
We write this as an equation
The original price *110% = final price
This is because the original price is itself (100%) added with 10%
Plug in the known final price
Original Price * 110% = 796.40
Convert 110% to a decimal because the other numbers- such as the final price are also decimal numbers.
Convert 110% to a decimal by moving the decimal point up 2 spaces ( basically dividing it by 100)
110% = 1.1
So it is now
Original price *1.1 = 796.40
Divide both sides by 1.1 to isolate our unknown, the original price
Original price = $724
Answer:4
Step-by-step explanation:
64 divided by 16 is 4.y-step explanation
Answer:
Both graphs can be used.
Step-by-step explanation:
because the time and the difficultly of the grade both depend on how long they take. Therefore it would be both graphs can be used.
