Question

A spring with a force constant of 120 N/m is used to push a 0.27-kg block of wood against a wall

Answer 1

Answer

given,

Spring force constant = 120 N/m

mass of the wooden block = 0.27 Kg

coefficient of friction = 0.46

a) we know,  

   μ N = mg

   0.46 x N = 0.27 x 9.8

   N = 5.75 Newton

This should be the normal force on the block by the wall. Thus minimum spring force should be 5.75 newton.

             F = k x d

k = spring constant,

d = compression in spring)

5.75 = 120 x d

  d = 0.048 m

  d = 4.8 cm

b)  answer will  change if the mass of block is doubled.

mass becomes = 0.54 kg

the normal force  needed = 11.4 newton.

the compression becomes  = 9.6 cm.