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4 years ago

A spring with a force constant of 120 N/m is used to push a 0.27-kg block of wood against a wall

Physics

1 answer:

kvv77 [185]4 years ago

4 0

Answer

given,

Spring force constant = 120 N/m

mass of the wooden block = 0.27 Kg

coefficient of friction = 0.46

a) we know,

μ N = mg

0.46 x N = 0.27 x 9.8

N = 5.75 Newton

This should be the normal force on the block by the wall. Thus minimum spring force should be 5.75 newton.

F = k x d

k = spring constant,

d = compression in spring)

5.75 = 120 x d

d = 0.048 m

d = 4.8 cm

b) answer will change if the mass of block is doubled.

mass becomes = 0.54 kg

the normal force needed = 11.4 newton.

the compression becomes = 9.6 cm.

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Two charges (q1 = 3.8*10-6C, q2 = 3.2*10-6C) are separated by a distance of d = 3.25 m. Consider q1 to be located at the origin.

Sergio039 [100]

Answer:

The distance is 1.69 m.

Explanation:

Given that,

First charge $q_{1}= 3.8\times10^{-6}\ C$

Second charge $q_{2}=3.2\times10^{-6}\ C$

Distance = 3.25 m

We need to calculate the distance

Using formula of electric field

$E_{1}=E_{2}$

$\dfrac{kq_{1}}{x^2}=\dfrac{kq_{2}}{(d-x)^2}$

$\dfrac{q_{1}}{q_{2}}=\dfrac{(x)^2}{(d-x)^2}$

$\sqrt{\dfrac{q_{1}}{q_{2}}}=\dfrac{x}{d-x}$

$x=(d-x)\times\sqrt{\dfrac{q_{1}}{q_{2}}}$

Put the value into the formula

$x=(3.25-x)\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x+x\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})=3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}$

$x=\dfrac{3.25\times\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}}}{(1+\sqrt{\dfrac{3.8\times10^{-6}}{3.2\times10^{-6}}})}$

$x=1.69\ m$

Hence, The distance is 1.69 m.

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4 years ago

10x2poooop11111111qq64

yulyashka [42]

Answer:

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3 years ago

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Answer:

C, Tibia.

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3 years ago

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Which of the following describe advantages of using radio waves over other electromagnetic waves to transmit information to Eart

Whitepunk [10]

The correct options are:

"Radio waves have a lower frequency, which makes them safer for humans."

"Radio waves take less energy to produce."

<h3>Why do we radio waves over other electromagnetic waves to transmit information to Earth? </h3>

Radio waves are electromagnetic waves with frequencies on the range from 10 KHz to 10 THz.

Now, remember that all electromagnetic waves have the same speed, which is the speed of light, and the energy of a wave is proportional to its frequency.

Particularly, we can see that radio waves have small frequencies (smaller than infrared light) so these waves carry very little energy.

With that in mind, the correct options are.

"Radio waves have a lower frequency, which makes them safer for humans."

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These are the two main reasons of why we use radio waves.

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2 years ago

According to Wien's Law, how many times hotter is an object whose blackbody emission spectrum peaks in the blue, at a wave lengt

scZoUnD [109]

Answer:1.55 times

Explanation:

Given

First wavelength $(\lambda _1)=450 nm$

Second wavelength $(\lambda _2)=700 nm$

According wien's diplacement law

$\lambda T=constant$

where $\lambda =wavelength$

T=Temperature

Let $T_1 and T_2$ be the temperatures corresponding to $\lambda _1 & \lambda _2$ respectively.

$\lambda _1\times T_1=\lambda _2\times T_2$

$\frac{T_1}{T_2}=\frac{\lambda _2}{\lambda _1}$

$\frac{T_1}{T_2}=\frac{700}{450}=1.55$

Thus object with $\lambda 450 nm$ is 1.55 times hotter than object with wavelength $\lambda =700 nm$

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3 years ago