Answer:
density = 0.16[gr/cm^3] = 160 [kg/m^3]
Explanation:
To solve this problem we must use the definition of density which tells us that this is equal to the relationship between mass and volume. In this way we have:
Since the body is a cube, its sides are equal we have:
v = 5 * 5 * 5 = 125 [cm^3]
m = 20 [grams]
density = m / v
density = 20/125
density = 0.16 [grams/cm^3]
Now if we convert the units to the international system, we have:
![0.16[\frac{gr}{cm^{3} } ]*\frac{1kg}{1000gr} *\frac{100^{3} cm^{3} }{1^{3} m^{3} } \\= 160 [kg/m^{3} ]](https://tex.z-dn.net/?f=0.16%5B%5Cfrac%7Bgr%7D%7Bcm%5E%7B3%7D%20%7D%20%5D%2A%5Cfrac%7B1kg%7D%7B1000gr%7D%20%2A%5Cfrac%7B100%5E%7B3%7D%20cm%5E%7B3%7D%20%7D%7B1%5E%7B3%7D%20m%5E%7B3%7D%20%7D%20%5C%5C%3D%20160%20%5Bkg%2Fm%5E%7B3%7D%20%5D)
Answer:
Speed in kilometer/hour = 6 kilometer / hour
Explanation:
Given;
Time taken to cover distance = 15 minute = 15 /60 = 0.25 hour
Distance of school = 1.5 kilometer
Find:
Speed in kilometer/hour
Computation:
Speed in kilometer/hour = Distance / Time
Speed in kilometer/hour = Distance of school / Time taken to cover distance
Speed in kilometer/hour = 1.5 / 0.25
Speed in kilometer/hour = 6 kilometer / hour
Answer:
V1 = 15m/s[45o E of N.] = 45o N. of E.
V2 = 18m/s[5o N. of E.].
Vr = 15m/s[45o] + 18m/s[5o].
Vr = 15*Cos45+15*sin45 + 18*Cos5+18*sin5.
Vr = (10.61+10.61i) + (17.93+1.57i) = 28.54 + 12.18i.
Magnitude = sqrt(28.54^2 + 12.18^2) =
Tan A = Y/X = 12.18/28.54 = 0.42887. A =
0 2
posted by Henry
Apr 8, 2017
31 m/s
23 ° north of east
Explanation:
Answer:
Power = 606.83 hp/mile
Explanation:
Given data:
diameter of pipeline is 36 inches = 3ft
flow rate is 590,000 barrels per day = 28.755 ft^3/sec
temperature of pipe = 46 degree celcius
length of pipe is 1.9 mile = 10032 ft
velocity of flow
applying bernouli eq at two point in pipeline
P1 = P2
v1 = v2
z1 = z2 so we have
POwer 
Power P = 1152.99 hp 0
power needed for each mile 
