Answer:
a) 10.54 sec
b) 284.58 m
c) 29.406 m/s
d) 39.92 m/s
Explanation:
Given data:
velocity of spacecraft = 27.0 m/s
rate of free fall acceleration is 2.79 m/s^2
distance of moving aircraft from mooon surface is 155 m
a. from kinematic eqaution of motion we have
where y = 155 m
Vi = 0 as this relation is for vertical motion, so the 27.0 m/s is not included
and a = 2.79 m/s^2.
Solving for t we get
t = 10.54 sec
b.
we know that
c. from the kinematic formula
v = u + at
v = 29.4066 m/a
d.
v = 39.92 m/s
Missing part of the text:
"Two masses, m1 = 2.12 kg and m2 = 9.01 kg are on a horizontal frictionless surface and they are connected together with a rope as shown in the figure."
and missing figure (see attachment)
Solution:
We can write Newton's second law for the whole system m1-m2 and for m2 only (2 equations). Only one force (F) acts on the m1-m2 system, while if we consider m2 only we have two forces acting on it: F and T (tension), in the opposite direction. So, the two equations are
where a is the acceleration of the system.
From the first equation we get
and substituting it inside the second equation, we get
re-arranging, we get
Using
,
, and using the maximum value of T that is allowed not to break the rope (T=55 N), we can find the maximum allowed value for F:
I need more information to further answer this question.
I attached a free body diagram for a better understanding of this problem.
We start making summation of Moments in A,
Then we make a summation of Forces in Y,
At the end we calculate the angle with the sin.
The answer is: [D]: "have rings and bands" .
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