Answer:A language is a structured system of communication. Language, in a broader sense, is the method of communication that involves the use of – particularly human – languages. The scientific study of language is called linguistics
Explanation:
Answer:
Distancia = 42.5 metros
Explanation:
Dados los siguientes datos;
Velocidad del sonido = 340 m/s
Tiempo = 8 segundos
Para encontrar la distancia desde la que se escuchó el sonido;
Distancia = velocidad/tiempo
Sustituyendo en la fórmula, tenemos;
Distancia = 340/8
Distancia = 42.5 metros
Answer:
1.) 1620 km/h^2
2.) 2.7 km
Explanation:
1.) Given that the car start from rest. The initial velocity U will be equal to zero. That is,
U = 0.
Final velocity V = 54 km/h
Time t = 2 minute = 2/60 = 1/30 hour
Acceleration a will be change in velocity per time taken. That is,
a = ( V - U )/ t
Substitute V, U and t into the formula
a = 54 ÷ 1/30
a = 54 × 30 = 1620 km/h ^2
2.) Distance travelled S by the car during the time can be calculated by using the 2nd equation of motion.
S = Ut + 1/2at^2
Substitute all the parameters into the formula
S = 54 × 1/30 + 1/2 × 1620 × (1/30)^2
S = 54/30 + 810 × 1/900
S = 54/30 + 810/900
S = (1620+810)/900
S = 2430/900
S = 2.7 km.
Therefore, distance travelled by the car during this time is 2.7 km
Answer:
(a) F = 1500 N.
(b) Ratio force to the antelepe's weight = 3.40
Explanation:
Force : This can be defined as the product of mass and the distance moved by a body. Its S.I unit is Newton. It can be represented mathematically as
F = Ma
Where F= force, M = mass (Kg) and a = Acceleration (m/s²)
Weight: This can be defined as the force on a body due to gravitation field. It is also measured in Newton (N). It can be represented mathematically as
W = Mg
Where W = weight of the body, M = mass of the body (Kg), g = Acceleration due to gravity.
(a)
F = Ma
Where M = 45kg,
a = unknown.
But we can look for acceleration Using one of the equation of motion,
v² = u² + 2gs
Where v= final velocity(m/s), u = initial velocity (m/s) g = 0 m/s, g = 9.8m/s² and s = height = 2.5m.
∴ v² = 2gs
v = √2gs = √(2×9.8×2.5)
v= √49 = 7m/s
With the force applied, the impala’s velocity must increase from 0 m/s to 7 m/s in 0.21 second
∴ a = (v-u)/t
a = (7-0)/0.21 = 7/0.21
a = 33.33 m/s².
F = 45 × 33.33 ≈ 1500
F = 1500 N.
(b)
Where F = Force = 1500 N
and W = Weight = Mg = 45 × 9.8 = 441 N
∴Ratio force to the antelepe's weight = F/W = 1500/441 = 3.40
Ratio force to the antelepe's weight = 3.40
Answer:
D
Explanation:
Emerald is not a variety of corundum rather its a variety of beryl.
A precious or semiprecious stone may or may not be transparent.
The value of gemstone is derived mostly by its rarity.
Pegmatite are igneous rocks found underground near sheets of igneous rocks called batholiths. They are a source of gemstones made of topaz, tourmaline, beryl spodumene and spessartine.
