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3 years ago

Could anybody help with this question? My teacher didn’t give a review so I’m not sure what to do. Any help is appreciated!

Mathematics

1 answer:

Allisa [31]3 years ago

8 0

Answer: 6

Step-by-step explanation: set the equations equal to each other then solve. plug that number into the equation for AB

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Assume the random variable X is normally distributed with mean mu equals 50 and standard deviation sigma equals 7. Compute the p

drek231 [11]

Answer:

The probability that X is less than 42 is 0.1271.

Step-by-step explanation:

The random variable X follows a Normal distribution.

The mean and standard deviation are:

E (X) = μ = 50.

SD (X) = σ = 7.

A normal distribution is continuous probability distribution.

The Normal probability distribution with mean µ and standard deviation σ is given by,

$f_{X}(\mu, \sigma)=\frac{1}{\sigma\sqrt{2\pi}}e^{-(x-\mu)^{2}/2\sigma^{2}};\ -\infty$

To compute the probability of a Normal random variable we first standardize the raw score.

The raw scores are standardized using the formula:

$z=\frac{x-\mu}{\sigma}$

These standardized scores are known as z-scores and they follow normal distribution with mean 0 and standard deviation 1.

Compute the probability of (X < 42) as follows:

$P(X$

*Use a z-table for the probability.

Thus, the probability that X is less than 42 is 0.1271.

The normal curve is shown below.

6 0

3 years ago

Not a question. just wanted to say I'm making a wand and it looks pretty sick

zhannawk [14.2K]

Answer:

oh ok thanks for free points

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Can someone help me find the equivalent expressions to the picture below? I’m having trouble

miss Akunina [59]

Answer:

Options (1), (2), (3) and (7)

Step-by-step explanation:

Given expression is $\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$ .

Now we will solve this expression with the help of law of exponents.

$\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}$

$=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}$

$=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}$

$=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}$

$=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}$

$=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }$ [Option 2]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$ [Option 1]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2$

$=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }$

$=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }$ [Option 3]

$2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }$

$=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}$ [Option 7]

Therefore, Options (1), (2), (3) and (7) are the correct options.

6 0

2 years ago

I need help with 4ourth grade math lesson 8 homework helper asap math

Dmitriy789 [7]

Answer:

sure

Step-by-step explanation:

3 0

3 years ago

A bookstore sold 25 books in 5 days. At this rate

Sonbull [250]

Answer:

20 days

Step-by-step explanation:

We multiply 25 by 4 to get 100, then multiply 5 by 4 to get 20.

5 0

2 years ago

Read 2 more answers