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lidiya [134]
3 years ago
8

At the beginning of the quarter there were 40 students in our class. At the final exam, there are only 32 students left. By what

percent did the class size decrease? by 96​
Mathematics
2 answers:
barxatty [35]3 years ago
8 0

Answer:

20 % decrease

Step-by-step explanation:

First find the number of students that left

40 -32 = 8

Take the number of students that left and divide by the original number of students

8/40

1/5

.20

20%

20 % decrease

Igoryamba3 years ago
4 0

Answer:

20% decrease ._.

Step-by-step explanation:

If u could subscribe to my friend penny_pg3d on YT, that would be great :)

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You purchase a car using a $20,000 loan with a 5% simple interest rate.
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A) I=prt; I=20,000(.05)(4) = $4000 b) I = prt; I = 20,000(.05)(2) = $2000 $4000-$2000 = $2000. You save $2000 by paying it off in 2 years vs. 4 years
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4 years ago
In a population of subjects, possess a certain characteristic. A sample of subjects selected from this population has subjects w
Dahasolnce [82]

Answer:

the values of the population and sample proportions is 0.64 and 0.6 respectively

Step-by-step explanation:

The computation of the values of the sample proportions and the population is shown below:

Given that

Let us assume the population be P

N= 1000

X = subjects possess specific characteristic = 640

So,

P  = X ÷ N

= 640 ÷ 1000

= 0.64

And, the sample proportion is  

n = 40

x = subjects possess specific characteristic = 24

p =X ÷ N

= 24 ÷ 40

= 0.6

hence, the values of the population and sample proportions is 0.64 and 0.6 respectively

5 0
3 years ago
Use function notation to write a recursive formula to represent the sequence: 4, 8, 12, …
faust18 [17]

Answer:

A.f(n) = f(n − 1) + 4

Step-by-step explanation:

4+4 = 8

8+4 = 12

We are adding 4 to the term  before it

f(n) = f(n-1) +4

4 0
4 years ago
Read 2 more answers
The American Association of Individual Investors conducts a weekly survey of its members to measure the percent who are bullish,
Andreyy89

Answer:

p-value = 0.8572

The current sample results do not show that bullish sentiment differs from its long-term average of 0.39, that is, the sample results show that there is no difference between the current bullish sentiments and the long-term average of 0.39.

Step-by-step explanation:

For hypothesis testing, the first thing to define is the null and alternative hypothesis.

The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.

While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.

For this question, we want to test if the current sample results show that bullish sentiment differs from its long-term average of 0.39.

The null hypothesis would be that there isn't enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.

The alternative hypothesis is that there is enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.

Mathematically, if the population proportion of bullish members for that period/week is p.

The null hypothesis is represented as

H₀: p = 0.39

The alternative hypothesis is represented as

Hₐ: p ≠ 0.39

To do this test, we will use the z-distribution because although, no information on the population standard deviation is known, 5he sample size is large enough for the sample properties to approximate the population properties.

So, we compute the z-test statistic

z = (x - μ)/σₓ

x = sample proportion of bullish members = 0.385

μ = p₀ = the standard we are comparing against = 0.39

σₓ = standard error = √[p(1-p)/n]

where n = Sample size = 300

σₓ = √[0.385×0.615/300] = 0.0280935936 = 0.02809

z = (0.385 - 0.39) ÷ 0.02809

z = -0.1779765192 = -0.18

checking the tables for the p-value of this z-statistic

Significance level = 0.05

The hypothesis test uses a two-tailed condition because we're testing in both directions.

p-value (for t = 0.18, at 0.05 significance level, with a two tailed condition) = 0.857153

The interpretation of p-values is that

When the (p-value > significance level), we fail to reject the null hypothesis and when the (p-value < significance level), we reject the null hypothesis and accept the alternative hypothesis.

So, for this question, significance level = 0.05

p-value = 0.857153

0.857153 > 0.05

Hence,

p-value > significance level

This means that we fail to reject the null hypothesis & say that there isn't enough evidence from the sample results to suggest that the bullish sentiment differs from its long-term average of 0.39.

Hope this Helps!!!

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