P = ab^2
q = a^3 b
p = a * b * b
q = a*a*a * b
Pairing the duplicates we have LCM = a*a*a*b*b = a^3 b^2 answer
Answer:
They can make 10 different groups of three.
Step-by-step explanation:
The order in which the people are in the car is not important, so we use the combinations formula to solve this question.
Combinations formula:
is the number of different combinations of x objects from a set of n elements, given by the following formula.

How many different groups of three can the five of them make?
Combinations of 3 from a set of 5. So

They can make 10 different groups of three.
If the denominator does not equal 0, the equivalent expression of
is 

<h3>How to determine the equivalent expression?</h3>
The expression is given as:

Divide 14 by 7

Apply the law of indices

Evaluate the differences in the exponents

Hence, the equivalent expression of
is 
Read more about equivalent expressions at:
brainly.com/question/2972832
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I think transition, reflection, transition, and reflection.
So,
First, we find the prime factored form (P.F.F.) of 65 and 91.
P.F.F. of 65: 5 * 13
P.F.F. of 91: 7 * 13
Find the common numbers
13
13 = G.C.F.
Note: This method works for finding any G.C.F. (find common primes)