Please consider the complete question.
The base of a solid oblique pyramid is an equilateral triangle with a base edge length of 18 inches. What is the height of the triangular base of the pyramid?
First of all, we will draw an equilateral triangle.
Since the given triangle is equilateral triangle, so all sides will have same length that is 18 inches.
We know that height of an equilateral triangle is
, where a is side length of equilateral triangle.


Therefore, the height of the given equilateral triangular base will be
inches and option B is the correct choice.
Answer:
B is the answer. It keeps going up by 3 every time.
Step-by-step explanation:
To solve for X you must get x by itself so let's get started
-4x+13=6x-7
subtract 13 from both sides
-4x=6x-20
subtract 6x from both sides
-10x=-20
divide both sides by -10
x=2
to check if this is correct plug in x into original equation
-4 (2)+13=6 (2)-7
-8+13=12-7
5=5
answer x=2 holds true :)
A number composed by 5 digits: in decimal each digit can be 0,1..9 so a 5 digit number can express numbers from 0 to 99999 and they are 10 5 = 100 , 000 . A 5 bit number is something similar but with bits, i.e. binary digits.
Hope this helps ;)
Answer:
14.2 is the diameter.
Step-by-step explanation:
The radius squared = 52.
What you have given is the general equation of the circle with a center at (2,-3) and a radius of sqrt(52)
You can break the 52 down.
sqrt(52) = sqrt(4 * 13) = 2 sqrt(13). Notice that 4 is a perfect square.
d = 2*radius.
d = 2(2 sqrt(13) )
d = 4 sqrt(13)
That is the diameter. You want it to the nearest 1/10
d = 14.222 but it is to the nearest 1/10
d = 14.2