Answer:
Option (c) Remote code exploits aim to escalate attackers’ privileges, while XSS attacks aim to gain access only
Explanation:
- XSS stands for Cross-site Scripting. In this types of attacks, a malicious code is injected in the trusted web sites and it sends the malicious code into the users. The users think that the genuine code was sent but not.
- This involves sending server side scripts which are executed by the user and these may even change the html pages too.
- Remote code exploitation means the user can inject the code and try to gain access. Usually, all the programming languages have evaluation functions if used the user can try to gain the access with this evaluation functions.
- This can lead to the compromise of the whole web server too.So, it is not a good practice to use the evaluation functions by the developers.
- In this type of attack, the attacker tries to inject the code remotely.
- Option (c) is correct and options (a),(b) and (d) are wrong options.
Answer:
Hi!
The correct answer is E.
Explanation:
void change(int ar[], int low, inthigh) {
int temp;
if(low< high) { <em>// here ask if the positions low and high of the array are the same.</em>
temp= ar[low]; <em>// first, saves the element on ar[low] in temp.</em>
ar[low]= ar[high]; <em>// second, the element on ar[high] in ar[low]. First switch.</em>
ar[high]= temp; <em>// third, saves the element on temp in ar[high]. Complete switch.</em>
change(ar,low + 1, high - 1); <em>// Recursive call, adding one position to low, and subtracting one position to high. </em><em>Important: </em><em>When low and high have the same value, the recursive call will finish.</em>
}
}
Result: Switch the lower half of elements in the array with the upper half.
Yes, It's important to do that. The more shield you have the more you stay alive between 1v1s
Hope this helps!
It would be A-in house counsel.
