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Savatey [412]
3 years ago
12

Show a parse tree and a leftmost derivation for : B = C * (A + B)

Computers and Technology
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

mhyfocnu,sobgu,kvngwugwe8hri

Explanation:

sovijbjxyzkuvcg

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Answer:

yeet mom

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Plz show working for binary addition. please solve. 11000 + 110101 + 101011​​
IrinaVladis [17]

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thats would be 222112 <3

Explanation:

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The ________ is a consortium of organizations that develops web protocols and sets standards.
zlopas [31]

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W3C

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W3C is the consortium of organizations.

8 0
3 years ago
A bowl contains 20 candies; 15 are chocolate and 5 are vanilla. You select 5 at random. What is the probability that all 5 are c
Sindrei [870]

Answer: 0.1937

Explanation:

Given : A bowl contains 20 candies; 15 are chocolate and 5 are vanilla.

If we select 5 candies, then the number of ways to select them is given by permutations.

The number of ways to select 5 candies is given by :-

^{15}P_5=\dfrac{15!}{(15-5)!}=\dfrac{15\times14\times13\times12\times11\times10!}{10!}=360360

The number of ways of selecting any 5 candies out of 20:-

^{20}P_5=\dfrac{20!}{(20-5)!}\\\\=\dfrac{20\times19\times18\times17\times16\times15!}{15!}\\\\=1860480

Now, the probability that all 5 are chocolate :-

=\dfrac{360360}{1860480}=0.193691950464\approx0.1937

Hence, the probability that all 5 are chocolate =0.1937

5 0
4 years ago
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Your assignment is to write an assembly language program which read a string and print it in uppercase. This program asks the us
const2013 [10]

Answer:

try this

Explanation:

MSG1 DB 10,13,'enter any string:-$'

MSG2 DB 10,13,'converted string is:-$'

P1 LABEL BYTE

M1 DB 0FFH

L1 DB?

P11 DB 0FFH DUP<'$'>

DATA ENDS

DISPLAY MARCO MSG

MOV AH,9

LEA DX,MSG

INT 21H

ENDM

CODE SEGMENT

ASSUME CS: CODE,DS:DATA

START:

MOV AX,DATA

MOV DS,AX

DISPLAY MSG1

LEA DX,P1

MOV AH,0AH

INT 21H

DISPLAY MSG2

LEA SI,P1

MOV CL,L1

MOV CH,0

CHECK:

CMP[SI],61H

JB DONE

CMP[SI],5BH

UPR: SUB[SI],20H

DONE: INC SI

LOOP CHECK

DISPLAY P11

MOV AH,4CH

INT 21H

CODE ENDS

END START

4 0
3 years ago
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