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3 years ago

Evaluate the following expression: 5+7(3x+y) when x=12, y=8

Mathematics

2 answers:

Mice21 [21]3 years ago

7 0

Answer:

The answer is 313.

Step-by-step explanation:

You have to substitite the values of x and y into the expressions :

$5 + 7(3x + y)$

$let \: x = 12,y = 8$

$5 + 7(3 \times 12 + 8)$

$= 5 + 7(36 + 8)$

$= 5 + 7(44)$

$= 5 + 308$

$= 313$

timofeeve [1]3 years ago

5 0

First step is 5+7(36x+8y) because you have to distribute

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Quadratics need help making parabola

timama [110]

Answer:

The equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ , whose real vertex is $(x,y) = (2, -5.333)$ , not $(x,y) = (2, -5)$ .

Step-by-step explanation:

A parabola is a second order polynomial. By Fundamental Theorem of Algebra we know that a second order polynomial can be formed when three distinct points are known. From statement we have the following information:

$(x_{1}, y_{1}) = (-2, 0)$ , $(x_{2}, y_{2}) = (6, 0)$ , $(x_{3}, y_{3}) = (0, -4)$

From definition of second order polynomial and the three points described above, we have the following system of linear equations:

$4\cdot a -2\cdot b + c = 0$ (1)

$36\cdot a + 6\cdot b + c = 0$ (2)

$c = -4$ (3)

The solution of this system is: $a = \frac{1}{3}$ , $b = - \frac{4}{3}$ , $c = -4$ . Hence, the equation of the parabola is $y = \frac{1}{3}\cdot x^{2}-\frac{4}{3}\cdot x -4$ . Lastly, we must check if $(x,y) = (2, -5)$ belongs to the function. If we know that $x = 2$ , then the value of $y$ is: